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kow [346]
2 years ago
12

Describe Computing Device in your own words.

Computers and Technology
1 answer:
fomenos2 years ago
5 0

Answer:

a computing device is a functional unit that can perform numerous arithmetic operations and logic operations without human intervention

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Some machine/items/gadget having only hardware​
shepuryov [24]
Yeh it’s becoz they work with hardware that’s why
6 0
3 years ago
Non-preemptive Shortest Job First (SJF) scheduling policy is not optimal if:
ivann1987 [24]

Answer:

The answer is A

Explanation:

Basically, Shortest job first (SJF) is a scheduling policy that selects jobs on queue for execution  within a short execution time.

From the definition of SJF above, it means that there are a lot of process on queue and the (SJF) job is to receive processes on queue to execute within a short execution time.

Therefore, if all the jobs or process arrives at the SJF at the same time, the SJF will forfeit one of its major purpose which is scheduling of jobs.

That will therefore not make Non-preemptive Shortest Job First (SJF) not function at its optimal point.

4 0
3 years ago
Consider the following algorithms. Each algorithm operates on a list containing n elements, where n is a very large integer.
DochEvi [55]

We have that the appropriate statement will be

  • An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

From the question we are told

Consider the following <u>algorithms</u>. Each <u>algorithm</u> operates on a list containing n <em>elements</em>, where n is a very large <u>integer</u>.

I. An algorithm that accesses each <u>element</u> in the list twice.

II. An <em>algorithm </em>that accesses each <u>element </u>in the list n times.

III. An <u>algorithm</u> that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the <em>algorithms </em>run in <em>reasonable </em>time?

<h3>Algorithm  </h3>

Generally In order to get <em>admission </em>to every thing in the list twice, the algorithm has to traverse the listing twice,

which leads to 2*n entry to operations.

And if the every factor is accessed n times, the listing will be traversed n time, which leads to n^2 get right of entry to operations.

If n is a very giant <em>integer</em>, each 2*n and n^2 are plenty larger.

So, there will be <em>solely </em>ten entry to operations and this algorithm will have a sensible jogging time.

Therefore

An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

For more information on  algorithm  visit

brainly.com/question/950632

4 0
2 years ago
Which of the following are possible ways to
Andru [333]

Answer:

employ ability assessments and the ability to perform tasks

Explanation:

6 0
3 years ago
Read 2 more answers
Assume X and Y are indepndent. Assume that X has mean 10 and standard deviation 8. Assume Y has mean 12 and standard deviation 6
Vitek1552 [10]

Answer:

\sigma_z = 10

Explanation:

Given

\bar x = 10

\sigma_x = 8

\bar y = 12

\sigma_y = 6

z = x + y

Required

\sigma_z

This is calculated as:

\sigma_z = \sqrt{Var(x) + Var(y)}

Calculate Var(x)

We have:

Var(x) = \sigma_x^2

Var(x) = 8^2

Var(x) = 64

Calculate Var(y)

We have:

Var(y) = \sigma_y^2

Var(y) = 6^2

Var(y) = 36

So, we have:

\sigma_z = \sqrt{Var(x) + Var(y)}

\sigma_z = \sqrt{64 + 36}

\sigma_z = \sqrt{100}

\sigma_z = 10

6 0
3 years ago
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