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konstantin123 [22]
3 years ago
8

Write in standard form: An equation of a line which has a slope of 2/3 and contains the point (0,2)

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

The equation of a line with slope 2/3 and point (0,2) is 3y - 2x = 6

The equation of a line is given as

y = mx + c

m = slope

c = intercept

The data given are

  • slope (m) = 2/3
  • x = 0
  • y = 2
<h3>Intercept</h3>

Put in the values into the equation above and solve for the intercept.

y = mx + c\\2 = 2/3(0) + c\\c = 2

<h3>Equation of the line</h3>

y = 2/3x +2\\

Multiply through by 3

y = 2/3(x) +2\\y(3) = (3)2/3x + 2(3)\\3y = 2x + 6\\3y - 2x = 6

From the above calculation, the equation of a line is 3y - 2x = 6

Learn more about equation of a line here;

brainly.com/question/13763238

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Answer:

Step-by-step explanation:

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8 0
3 years ago
Use the coordinate grid to determine the coordinates of point A;
faltersainse [42]

Answer:

Step-by-step explanation:

The coordinates of point P are (-1.4,0.6)

Step-by-step explanation:

We are given A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole unit of the grid.

that means each grid has a value of 0.2.

" A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis "

As P lies on the left of the y-axis and above the x-axis hence the x-value will be negative and y-value will be positive.

According to the given information P lies 7 grid lines to the left of y-axis.

i.e. it has x-value -7×0.2= -1.4

and 3 grid lines above the x-axis i.e. it has y-value:

y-value= 3×0.2=0.6

Hence, the coordinates of Point P are (-1.4,0.6).

Click to let others know, how helpful is it

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8 0
4 years ago
Read 2 more answers
Evaluate if x=-4 and y=13 3(2x- y)
Katena32 [7]

Answer:

-63

Step-by-step explanation:

6x - 3y

= 6 × -4 - 3 × 13

= -24 - 39

= -63

8 0
3 years ago
Given the triangle shown below, find the length of [BC]​
marshall27 [118]

Hyp²=ADJ²+OPP²

28²=17²+X²

784=289+x²

x²=784-289

x²=495

x=22

here is your answer 22

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3 years ago
Consider the linearization, L(x) of the curve y = x at (36, 6). What are the least and greatest values of x for which this linea
docker41 [41]
X=42,45
That’s the answer of your question
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4 years ago
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