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2 years ago

Pls i need help real fast i have 3 min to submit this

Mathematics

1 answer:

Neko [114]2 years ago

6 0

Answer:

I was having trouble submitting a text answer, so I attached a file. Hope it helps.

Step-by-step explanation:

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Will give extra points to whoever solves this

Hatshy [7]

Answer:

Step-by-step explanation:

As Angle 5 and Angle 4 form a linear pair, they are supplementary.

Hence,

$Hence,\\Angle\ 5\ +\ Angle\ 4\ =\ 180\\(3x+7)+(9x-43)=180\\12x+(-36)=180\\12x=180+36\\12x=216\\x=18\\\\Hence, Obtuse\ Angle\ UPS = Angle\ 4 + 90\\Hence,\\Obtuse\ Angle\ UPS\ = (3x+7)+90\\\\We\ know\ that\ x=18 \\Hence, Angle\ 4\ = (3*18+7)\\=(54+7)\\=61\\\\Obtuse\ Angle\ UPS\ = 61+90\\=151\\\\\\Reflex\ Angle\ UPS\ = 360-151\\=209$

3 0

3 years ago

When x is decreased by 129 and then that number is multiplied by 129, the result is 129. What is the value of x?

myrzilka [38]

Answer:

Step-by-step explanation:

twice the difference of a number and 3 is added to 4

4 0

3 years ago

There are

stepladder [879]

Answer:

i think it might be 0.43

Step-by-step explanation:

Just divide 13/30 and it should you you that proportion as a percentage I think! Sorry if I might've given you the wrong answer but just trynna help!

have a nice day

6 0

3 years ago

Read 2 more answers

41. Assuming that a man can complete the work alone in x days, his work in four days would be: a) b) X X C d) 4x x 42. If a man

Schach [20]

Percentage and ratio word problems require understanding of the relationship between variables from which the question is formed

The options that give the correct values of the duration of the work are;

$41. \ c) \ \dfrac{4}{x}$

$42. \ d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. a) 35 days

44. c) 21·a + 28·b = 1

45. c) (42, 56)

Reasons:

41. Number of days it takes a man to complete the work alone = x days

Therefore;

$The \ work \ done \ by \ the \ man \ in \ one \ day = \dfrac{1}{x}$

$The \ work \ done \ in \ four \ days \ by\ the \ man = 4 \times \dfrac{1}{x} = \dfrac{4}{x}$

The correct option is $c) \ \dfrac{4}{x}$

42. Number of days it takes a man to complete the work alone = x days

$Work \ done \ by \ a\ man \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ four \ men \ in \ one \ day = \dfrac{4}{x}$

Number of days it takes a boy to complete the work alone = y days

$Work \ done \ by \ a \ boy \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ six \ boys \ in \ one \ day = \dfrac{6}{y}$

4 men and 6 boys work for 5 days to complete the work

Therefore, work done by 4 men and 6 boys in 1 day is therefore;

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

The correct option is therefore;

$d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. As per the case study, we have;

Case 1

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

Which gives;

$\dfrac{6\cdot x + 4\cdot y}{y \cdot x} = \dfrac{1}{5}$

30·x + 20·y = y·x

Case 2

$\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$

Which gives;

$\dfrac{4\cdot x + 3\cdot y}{y \cdot x} = \dfrac{1}{7}$

28·x + 21·y = y·x

Therefore;

30·x + 20·y = 28·x + 21·y

∴ 2·x = y

Plugging in the value of y = 2·x, in Case 1 gives;

$\dfrac{4}{x} + \dfrac{6}{2 \cdot x} = \dfrac{1}{5}$

$\dfrac{2 \times 4 + 6}{2 \times x} = \dfrac{14}{2 \times x} =\dfrac{7}{x} = \dfrac{1}{5}$

7 × 5 = x

x = 7 × 5 = 35

The number of days, x, it takes a man to complete the work alone, is given by option; a) 35 days

44. For the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , if $a = \dfrac{1}{x}$ , and $b = \dfrac{1}{y}$ , we have;

$3 \cdot a+ 4\cdot y = \dfrac{1}{7}$

21·a + 28·y = 1

The correct option is option C. 21·a + 28·b = 1

45. A solution to the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , is given by the values of x, and y, that gives;

$\dfrac{1}{14} + \dfrac{1}{14} = \dfrac{1}{7}$

We have;

3 × 14 = 42

4 × 14 = 56

Therefore, a solution to the equation is (42, 56)

The correct option is $c) \ \underline{ (42, \ 56)}$

Learn more here:

brainly.com/question/11825953

brainly.com/question/14626596

brainly.com/question/15573651

3 0

2 years ago

What is the greatest common factor of 19x^7 and 3x^5

Anton [14]

Hi the answer is x^5.
19 is a prime number, so 3 cannot be a factor. However, bother terms contain x^5, this is the greatest common factor.

6 0

4 years ago