There are 500 even numbers from 1 to 1000 starting with 2 and ending with 998. The sequence of even numbers is an arithmetic sequence with a common difference of 2. Using the equation for the arithmetic series,
S = (a1 + an)(n/2)
and substituting,
S = (2 + 998)(500/2)
we get,
S = 250,000
Therefore, the sum of all even numbers between 1 and 1000 is 250,000.
I’m pretty sure that it’s 3/0.5 Hope I helped
Answer:
The answer to your question is below
Step-by-step explanation:
csc²x - csc²x cos²x = 1
Process
1.- Convert the second term to sines
csc²x - cos²x/sin²x = 1
2.- Convert cos²x/sin²x to cot²x
csc²x - cot²x = 1
3.- Solve for csc²x
csc²x = 1 + cot²x
We have verified it, because there is a Pythagorean identity which sets that
csc²x = 1 + cot²x
Let, Age of Faith = x
Age of this mother = 5x
Then, x+5x = 30
6x = 30
x= 5
So, age of faith is 5 years.
Hope this helps!
