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3 years ago

Choose a value for b so that the relation below is not a function.

Mathematics

1 answer:

kirill [66]3 years ago

3 0

I believe it’s B because it is not a function if there are 2 x values that are the same.

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This connects to the last one I did

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3 years ago

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What is the conversion factor to convert kilometers to miles?

Ierofanga [76]

Answer: approximately km*1.61=m

Step-by-step explanation:

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3 years ago

What is the domain of f(x)=5x^2 2x-1

adoni [48]

Domain of 5x^2 + 2x - 1 is all real numbers.

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4 years ago

Bobby put 1/3 of his lawn mowing money into his savings and uses the remaining 2/5 to buy a video game. If he has $12 left, how

Alexeev081 [22]

Given:

Bobby put 1/3 of his lawn mowing money into his savings

He uses the remaining 2/5 to buy a video game.

He has $12 left.

To find:

The amount did he have at first.

Solution:

Let x be the initial amount.

Bobby put 1/3 of his lawn mowing money into his savings. So, the remaining amount is

$x-\dfrac{1}{3}x=\dfrac{2}{3}x$

He uses the remaining 2/5 to buy a video game. Then the remaining amount is

$Remaining=\dfrac{2}{3}x-\dfrac{2}{3}x\times \dfrac{2}{5}$

$Remaining=\dfrac{2}{3}x-\dfrac{4}{15}x$

$Remaining=\dfrac{10x-4x}{15}$

$Remaining=\dfrac{6x}{15}$

$Remaining=\dfrac{2x}{5}$

It is given that the remaining amount is $12.

$12=\dfrac{2x}{5}$

$12\times 5=2x$

$60=2x$

Divide both sides by 2.

$\dfrac{60}{2}=x$

$30=x$

Therefore, Bobby have $30 at first.

6 0

3 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago