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3 years ago

If it takes 25 liters of gas to drive 150 miles, how many miles can be driven

Mathematics

2 answers:

Gala2k [10]3 years ago

8 0

Answer:210 because 150 divided by 25 is 6 and 35 times 6 is 210

Step-by-step explanation:hope this helps : )

sweet [91]3 years ago

6 0

210 miles would use up 35 litres

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Two angles are supplementary. The measure of one angle is 4 more than 7 times the other angle. Find the measures of both angles.

mylen [45]

Answer:

<u>The smaller angle measures 44° and the larger measures 136°</u>

Step-by-step explanation:

Smaller angle = x

Larger angle = 3x + 4

Therefore, we have:

x + 3x + 4 = 180

4x = 180 - 4

4x = 176

x = 176/4

x = 44 ⇒ 3x + 4 = 136

The smaller angle measures 44° and the larger measures 136°

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3 years ago

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For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

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3 years ago

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Answer:

your answer would be A.

Step-by-step explanation:

Already you know that answers b and d are not an option because it is saying she can use OVER 45 dollars. So she has to use EQUAL or less then 45 dollars. So the answer has to be A or C. In answer C it is saying she can spend MORE then 2.50 for a bunch where she cant. She has to spend exactly or less then that amount. So your answer is A.

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4 years ago

How does adding the log together automatically mean that it is a factorial?

andreyandreev [35.5K]

Answer: The answer is given below.

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We will be using the following two properties of logarithm:

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The proof is as follows:

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Hence proved.

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3 years ago