Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
A = 9 (Sorry I can't do the other ones, I haven't learned those ones yet) Hope this helps!! :P
The answer is A because both numbers can be divided by 6 to get 5 : 9
Answer:
x-15).8 this is the answer
Step-by-step explanation:
Since the quantity under a square root must be greater than or equal to zero, you would solve for x by subtracting two, to get that 1/3x must be greater than or equal to zero, then divide by 1/3 on both sides to get that x must be greater than or -6, so the last answer is correct
