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ValentinkaMS [17]
3 years ago
6

Value of complex number i^7+1/i^4​

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

i^7 + \dfrac 1{i^4}\\\\=i^2 \cdot i^2 \cdot i^2  \cdot i + \dfrac 1{i^2 \cdot i^2}\\\\=(-1)(-1)(-1)i + \dfrac 1{(-1)(-1)} ~~~;[ i^2 = -1] \\\\\ = (-1)^3 i+ \dfrac 1{(-1)^2} \\\\=-i+1

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What exactly is your question?
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allsm [11]
The correct answer is y= 0.513(1.833)^x


Explain


We will use the equation on this form

Y=ab^x

Let’s us plug in the coordinates of first point

(X, y) , ( 9, 120)

We will have

Y=ab^x

120= ab^9

Our equation for a will be

Ab^9 = 120

ab ^9 / b^9 = 120/ b^9


a = 120/ b^9

So will have


Y= 120/ b^9 • b^x

Then we will plug in coordinates for the second point


( x,y) = ( 10, 220)

We will have

Y= 120/b^9 • b^x

220 = 120/b^9 • b^10-9


220= 120b

Divide both side by 120

B= 11/6

B= 1.833333 = 1.833



Let’s plug in the value b=11/6 to our equation for a


A= 120/b^9

A= 120/ 11/6^9

A= 120/11^9/6^9


A=120 • 6^9 / 11^9

= 0.51285 which equal to 0.513



So therefore the answer is

Y= 0.513(1.833)^x


I hope this help you

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