3 years ago

Value of complex number i^7+1/i^4

1 answer:

7 0

$i^7 + \dfrac 1{i^4}\\\\=i^2 \cdot i^2 \cdot i^2 \cdot i + \dfrac 1{i^2 \cdot i^2}\\\\=(-1)(-1)(-1)i + \dfrac 1{(-1)(-1)} ~~~;[ i^2 = -1] \\\\\ = (-1)^3 i+ \dfrac 1{(-1)^2} \\\\=-i+1$

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$\diamond\large\blue\textsf{\textbf{\underline{Question:-}}}$

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$\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}$

➪ First, subtract 5 on both sides:-

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Value of complex number i^7+1/i^4​

Value of complex number i^7+1/i^4