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IrinaK [193]
3 years ago
9

Please help me if you can it would mean a lot!

Mathematics
1 answer:
finlep [7]3 years ago
6 0
A) 242
B) 1652
C) 118
Hope this helps
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The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=
Leno4ka [110]
1 step: S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}, S_{3}=T_{1}+T_{2}+T_{3}, then
 S_{5}-S_{3}=T_{4}+T_{5}=5.

2 step: T_{n}=T_{1}*q^{n-1}, then 
T_{6}=T_{1}*q^{5}
T_{5}=T_{1}*q^{4}
T_{4}=T_{1}*q^{3}
T_{3}=T_{1}*q^{2}
and \left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right. will have form \left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right..

3 step: Solve this system  \left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right. and dividing first equation on second we obtain \frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}. So, \frac{(q-1)(q+1)}{q+1} = \frac{1}{2} and q-1= \frac{1}{2}, q= \frac{3}{2} - the common ratio.

4 step: Insert q= \frac{3}{2}into equation T_{1}*q^{3}*(q+1)=5 and obtain T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5, from where T_{1}= \frac{16}{27}.




5 0
3 years ago
Help me again? Thanks to whomever does! Please show work!
almond37 [142]
Can you post the picture in a different angle it’s hard to read it
6 0
3 years ago
Read 2 more answers
Can someone PLEASE help me :((
Mars2501 [29]
I think is inside and then outside. Not sure

Hope this helps!
6 0
3 years ago
What’s the difference???<br> Help please
RideAnS [48]

Answer: D

Step-by-step explanation:

An equation would look like this:

x+1=3

An expression would look like this:

x+1

As you can see, an expression has no equal sign. Conversely, an equation does. That is the primary difference between a(n) (algebraic) expression and equation.

7 0
3 years ago
Read 2 more answers
(Algebra 2)
vekshin1

Answer:

No

Step-by-step explanation:

loga(b) = 1/[logb(a)]

log3(9) = 2

log9(3) = ½

3 0
3 years ago
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