What is the value of x? <br><br> x=

If f(x)=4x^3 - 6x^2 + 2x - 5, then f(-2) = ___________

Art [367]

f(x)=4x^3 - 6x^2 + 2x - 5

f(-2)

Replace X with -2:

4(-2)^3 - 6(-2)^2 + 2(-2) - 5 =

Calulate the powers:

4(-8) - 6(4) +(-4) -5=

Multiply:

-32 - 24 -4 -5=

Subtract

-65

7 0

3 years ago

If anyone is good at math and likes to help someone that is not good with it I will give you brainliest

hammer [34]

Answer:

1st pic answer:

Slope= -3

Parallel slope= -3

Perpendicular slope = 1/3

2nd pic answers:

1 and 2 are parallel

1 and 3 are perpendicular

2 and 3 are perpendicular

Step-by-step explanation:

To find the slope in your first equation (6x+2y=1) you need to get y alone so that your equation will be in slope-intercept form (y=mx+b).

6x+2y=1 Start by subtracting the 6x over to the other side.

-6x -6x

2y= -6x+1 Next divide by 2 to get y completely alone.

$\frac{2y}{2} =\frac{-6x}{2}+\frac{1}{2}$

y= -3x+1/2

So to answer the first part your slope is -3. Parallel slope would be the same as your regular slope. Perpendicular would be the opposite, so that means you have to flip it and change the sign.

-3 flipped is -1/3

if you change the sign it becomes positive giving you 1/3

Part 2

Your first step would be to get all the equations into the slope-intercept form (y=mx+b). The second one is already in the form so we only need to change 1 and 3.

3y=5x+2 To get y alone you need to divide everything by 3.

$\frac{3y}{3}=\frac{5x}{3} +\frac{2}{3}$

y=5/3x+2/3 Before we work on equation 3 we can go ahead and compare equations 1 and 2.

1: y= $\frac{5x}{3} +\frac{2}{3}$

2: y= $\frac{5x}{3} +7$ Since 1 and 2 have the same slope they would be parallel.

Now to change equation 3.

6x+10y=8 Start by subtracting the 6x over to the other side.

-6x -6x

10y=-6x+8 Now divide everything by 10 to get y alone.

$\frac{10y}{10}=\frac{-6x}{10} +\frac{8}{10}$

y=-6x/10+8/10 Now we need to simplify the fractions using common factors. I'm going to use 2 for both equations, so you take -6 and 10 both divided by 2, which gives you -3 and 5(-3x/5). Now do the same with the other fraction. 8 and 10 divided by 2 gives us 4 and 5 (4/5)

3: y= $\frac{-3x}{5}+\frac{4}{5}$

2: y= $\frac{5x}{3} +7$

1: y= $\frac{5x}{3} +\frac{2}{3}$

Since three has an opposite slope of both 1 and 2 it would be perpendicular to both.

5 0

3 years ago

A map uses a scale of 1 in :20mi. Find the the actual distance of 5.5 inches on the map. help me

astraxan [27]

Answer:

110

Step-by-step explanation:

5.5 x 20 = 110

4 0

2 years ago

1. Identify each situation in which a quantity grows or decays by a constant percent rate per unit interval. A. The number of ca

zvonat [6]

Answer:

Step-by-step explanation:

1) For each situation to grow or decay by a constant percent rate, it must be exponential. Therefore, the correct examples are

A. The number of cars sold doubles every year. It is a 200% growth every year.

D. Each time you start a car engine the remaining engine life decreases by 0.0075%. A case of decay

E. The number of people creating cat videos increases by 15% percent every year.

F. Computer technology increases by a factor of 3 every five years.

2) this is a case of exponential decay. The expression for exponential decay is

y = b(1 - r)^t

y = final value

b = initial value

r = decay rate

t = time

Given that

r = 10% = 10/100 = 0.1

b = 50 kilograms

y = W kilograms

The relationship is

W = 50(1 - 0.1)^t

W = 50(0.9)^t

3 0

2 years ago

PLZ HELP PIC INCLUDED

Reil [10]

x = # of days

y = total calories

Simba = 1000 + 140x = y

Cuddles = 2650 - 190x = y

Let's set both of these equations equal to each other

1000 + 140x = 2650 - 190x

Add 190x to both sides and subtract 1000 from both sides.

330x = 1650

Divide each side by 330

x = 5

After 5 days, they will be consuming the same amount of calories.

To find out how many calories they will be consuming, let's plug 5 into our Simba equation.

1000 + 140(5) = y

Multiply 140 by 5

1000 + 700 = y

Simplify

1700 = y

They will be consuming 1,700 calories each day.

5 0

2 years ago

What is the value of x? x=