Line g is dilated by a scale factor of 1/2 from the origin to create line g'. Where are points E' and F' located after dilation,
and how are lines g and g' related?
(See attatchment)
ANSWER OPTIONS:
A- The locations of E' and F' are E' (−8, 0) and F' (0, 4), and lines g and g' intersect at point F.
B- The locations of E' and F' are E' (−4, 0) and F' (0, 2), and lines g and g' are the same line.
C- The locations of E' and F' are E' (−2, 0) and F' (0, 1), and lines g and g' are parallel.
D- The locations of E' and F' are E' (−1, 0) and F' (0, 0), and lines g and g' are not related.
(See attatchment)
ANSWER OPTIONS:
A- The locations of E' and F' are E' (−8, 0) and F' (0, 4), and lines g and g' intersect at point F.
B- The locations of E' and F' are E' (−4, 0) and F' (0, 2), and lines g and g' are the same line.
C- The locations of E' and F' are E' (−2, 0) and F' (0, 1), and lines g and g' are parallel.
D- The locations of E' and F' are E' (−1, 0) and F' (0, 0), and lines g and g' are not related.
1 answer:
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Previous balance:
+ $481,47→ 11/30
- $300,00 → 11/02
- $68,99 → 11 / 10
- $45,00 → 11/15
- $72,75 → 11/17
----------------------------
+ $481,47 - $113,26 =
+ $368,21
new balance:
+ $481,47→ 11/30
- $300,00 → 11/02
- $
→ 11 / 10 for -$58,99
- $45,00 → 11/15
- $
→ 11/17 for $ 0
-------------------------------------------------------------------------------------
+ $481,47 - $196,01 =
+$285,46
Answer:
+ $481,47→ 11/30
- $300,00 → 11/02
- $68,99 → 11 / 10
- $45,00 → 11/15
- $72,75 → 11/17
----------------------------
+ $481,47 - $113,26 =
+ $368,21
new balance:
+ $481,47→ 11/30
- $300,00 → 11/02
- $
- $45,00 → 11/15
- $
-------------------------------------------------------------------------------------
+ $481,47 - $196,01 =
+$285,46
Answer:
Answer:
Step-by-step explanation:
slopes and equations:
find the equation thur ( 6,1 ) and (-2,-3)
find the slope m
m = (y2-y1) / (x2-x1 )
m = (-3 - 1) / (-2 -6)
m = -4 / -8
m = 1/2
now use the point-slope formula with our known slope
y-y1 = m(x-x1)
y-1 = 1/2(x-6)
y - 1 = 1/2x -3
y = 1/2x -3 +1
y = x -2
Find the equation parallel to y = 3x + 6 and thur (0,1)
Parallel means the same slope, the slope is 3 for the equation above.
use the slope-intercept formula again with the point given and the slope 3
y-1 = 3(x -0)
y - 1 = 3x
y = 3x +1
Find the equations perpendicular to 2x + y = 8 and the same y intercept as 4y = x + 3.
put both equations into proper form
y = -2x +6
y = x +
perpendicular means reciprocal slope and change the sign, the 2nd equation has an intercept of , so
y = 1/2x +
there you go Amanda :)