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TiliK225 [7]
3 years ago
12

SOMEONE HELPPPPPPPPP PLEEEASSEEEEEE IMMMM STUCCCCKKKKK PLLEASSE ILL GIVE YOU 24 POINTs: On Monday, Jan made withdrawals of $25,

$45, and $75 from her savings account. On the same day, her twin sister Julie made withdrawals of $35, $55, and $65 from her savings account.
1) write a sum of negative integers to show Jan's withdrawals on Monday. Find the total amount Jan withdrew.

2) write a sum of negative integers to show Julie's withdrawals on Monday. Find the total amount Julie withdrew.

3) Julie and Jan's brother also withdrew money from his savings account on Monday. He made three withdrawals and withdrew $10 more than Julie did. What are three possible amount he could have withdrawn?
Mathematics
2 answers:
kolezko [41]3 years ago
8 0
Just write down the negative values of each withdrawal and add up those values for the first two.
1. -25 + -45 + -75 = -145
2.-35 + -55 + -65 = -155
As for the third question, the brother took out $10 more than Julie, so he withdrew $165. A possible equation with possible values could be:
3. -15 + -65 + -85 = -165
Keep in mind that there are multiple ways to answer the third question and that's only one of them. Hope this helped!
Ksivusya [100]3 years ago
4 0

Answer:

1) $ 145

2) $ 155

3) $ 75, $ 25 and $ 65

Step-by-step explanation:

1) Given,

Changes in amount of Jan's account on Monday are,

- $25, - $45, and - $75,  ( negative sign indicates withdrawing )

Thus, total changes in balance = - 25 - 45 - 75 = - $ 145,

Hence, she withdrew $ 145 total.

2) Changes in amount of Julie's account on Monday are,

- $35, - $55, and - $65 ,

Thus, total changes in balance = - 35 - 55 - 65 = - $ 155

Hence, she withdrew $ 155 total.

3) ∵ Julie and Jan's brother made three withdrawals and withdrew $10 more than Julie did.

So, the total withdrawal amount of their brother = $ 165

So, the possible three widrawal are,

$ 75, $ 25, $ 65

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Solution:

<u>Note that:</u>

  • Abby's dog: 1.5 cups of food
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Looking at the information we got, we can say that Braxton's dog eats more. Let's put them into ratio form (Braxton's dog:Abby's dog)

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<u>Now, put them into fractions.</u>

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We can conclude that Braxton's dog eats 3 times more food.

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#1

The uniforms are numbered 0, 1, 2, ..., 99. That's 100 numbers. Half of them are odd and half of them are even. So the probability that any one of the uniforms is odd is 1/2 just like the probability that any one uniform is even is 1/2.

(a) The numbers on the uniforms are independent of one another. That is, the number of her cross-country uniform does not in any way determine the number on her basketball uniform and vice versa. This means that we can find the probability that each is odd and multiply these together using what is called the counting principle. The probability that all are odd is:
(1/2)(1/2)(1/2)=1/8

(b) This is done the same way we did part (a). Since the probability of any one uniform being odd is the same as it being even (1/2), the answer here is the same: (1/2)(1/2)(1/2)=1/8

(c) This problem differs from that in (a) and (b). There is only one way for all three uniforms to be odd numbers: (odd, odd, odd) or all even (even, even, even). However, there are multiple ways for the uniforms to be two odd and one even. If the uniforms are listed in order: cross-country, basketball, softball we can get exactly one even in any of three ways:
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Answer:

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Explanation:

Here given:

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