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valina [46]
3 years ago
10

the total height of the tower t and the antenna that stands on top of it a is 1729 feet. the difference in heights between the b

uilding and antenna is 279 feet. how tall is the tower.
Mathematics
1 answer:
Nataly [62]3 years ago
7 0
1729 - 279 = <span>1450

The tower is </span><span>1450 feet tall

I hope this helps! :)</span>
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What is the property of 2x32x5=2x5x32=
a_sh-v [17]
It would be communitive property
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The Collins family electric bill each month from April through September
mina [271]

Answer:

charge for electricity used over 700 kilowatt-hours per month.

Step-by-step explanation: thats the average for most houses

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3 years ago
Please help and show how you got the answer:
kari74 [83]

4 - 6n = 60 - 2n   <em>subtract 4 from both sides</em>

-6n = 56 - 2n    <em>add 2n to both sides</em>

-4n = 56    <em>divide both sides by (-4)</em>

n = - 14


-7 + 11p = 3p - 47       <em>add 7 to both sides</em>

11p = 3p - 40      <em>subtract 3p from both sides</em>

8p = -40      <em>divide both sides by 8</em>

p = - 5


3a - 28 - 7a = 10a          <em>combine like terms</em>

(3a - 7a) - 28 = 10a

-4a - 28 = 10a       <em>add 28 to both sides</em>

-4a = 10a + 28       <em>subtract 10 from both sides</em>

-14a = 28     <em>divide both sides by (-14)</em>

a = - 2


17 - 5r + 9r = 12 + 6r - 1       <em>combine like terms</em>

17 + (-5r + 9r) = (12 - 1) + 6r

17 + 4r = 11 + 6r      <em>subtract 17 from both sides</em>

4r = -6 + 6r     <em>subtract 6r from both sides</em>

-2r = -6      <em>divide both sides by (-2)</em>

r = 3


8(y - 7) = -2(y + 3)    <em>use distributive property: a(b + c) = ab + ac</em>

(8)(y) + (8)(-7) = (-2)(y) + (-2)(3)

8y - 56 = -2y - 6       <em>add 56 to both sides</em>

8y = -2y + 50     <em>add 2y to both sides</em>

10y = 50    <em>divide both sides by 10</em>

y = 5


-3(8k + 5) = 3(9 - k)      <em>use distributive property: a(b + c) = ab + ac</em>

(-3)(8k) + (-3)(5) = (3)(9) + (3)(-k)

-24k - 15 = 27 - 3k      <em>add 15 to both sides</em>

-24k = 42 - 3k      <em>add 3k to both sides</em>

-21k = 42     <em>divide both sides by (-21)</em>

k = -2


2(3v - 5) = 2(v - 11) - 4   <em>use distributive property: a(b + c) = ab + ac</em>

(2)(3v) + (2)(-5) = (2)(v) + (2)(-11) - 4

6v - 10 = 2v - 22 - 4

6v - 10 = 2v - 26      <em>add 10 to both sides</em>

6v = 2v - 16      <em>subtract 2v from both sides</em>

4v = -16      <em>divide both sides by 4</em>

v = -4


-2/3 (15x + 3) -3x - 9    <em>use distributive property: a(b + c) = ab + ac</em>

= (-2/3)(15x) + (-2/3)(3) - 3x - 9

= (-2)(5x) - 2 - 3x - 9

= -10x - 2 - 3x - 9                 <em>combine like terms</em>

= (-10x - 3x) + (-2 - 9)

= -13x - 11


3(1 - 9a) + 22a = 2(2a - 9) - 15

<em>use distributive property: a(b + c) = ab + ac</em>

(3)(1) + (3)(-9a) + 22a = (2)(2a) + (2)(-9) - 15

3 - 27a + 22a = 4a - 18 - 15          <em>combine like terms</em>

3 + (-27a + 22a) = 4a + (-18 - 15)

3 - 5a = 4a - 33      <em>subtract 3 from both sides</em>

-5a = 4a - 36       <em>subtract 4a from both sides</em>

-9a = -36      <em>divide both sides by (-9)</em>

a = 4


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<em>use distributive property: a(b + c) = ab + ac</em>

(-3)(3m) + (-3)(-10) - 7 = (-5)(m) + (-5)(1) + 3m

-9m + 30 - 7 = -5m - 5 + 3m           <em>combine like terms</em>

-9m + (30 - 7) = (-5m + 3m) - 5

-9m + 23 = -2m - 5     <em>subtract 23 from both sides</em>

-9m = -2m - 28        <em>add 2m to both sides</em>

-7m = -28      <em>divide both sides by (-7)</em>

m = 4

6 0
3 years ago
Is w = 8 a solution to the equation 5 + w = 58? Explain
sp2606 [1]

No.

Since w = 8, you must replace the variable with the number associated to it.

So, it would be 5 + 8 = 58

5 + 8 is not equal to 58, it is equal to 13.

If you wanted to find out what w was, simply subtract 5 on both sides.

w = 58 - 5

8 0
3 years ago
In ΔHIJ, the measure of ∠J=90°, JI = 4, HJ = 3, and IH = 5. What ratio represents the tangent of ∠I?
VMariaS [17]

Answer:

The ratio  \frac{3}{4} represents the tangent of ∠I

Step-by-step explanation:

Let us revise the trigonometry ratio

  • sin Ф =  \frac{opposite}{hypotenuse}
  • cos Ф =  \frac{adjacent}{hypotenuse}
  • tan Ф =  \frac{opposite}{adjacent}

In Δ HIJ

∵ m∠J = 90°

- Hypotenuse is the side which opposite to the right angle

∴ HI is the hypotenuse

∵ HJ = 3 units

∵ IH = 5 units

- Let us use Pythagoras Theorem to find HJ

∵ (HJ)² + (IJ)² = (IH)²

∴ 3² + (IJ)² = 5²

∴ 9 + (IJ)² = 25

- Subtract 9 from both sides

∴ (IJ)² = 16

- take √  for both sides

∴ IJ = 4 units

To find the tangent of ∠I find the opposite and adjacent sides to it

∵ HJ is opposite to ∠I

∵ IJ is adjacent to ∠I

- use the rule of tan above

∴ tan(∠I) = \frac{HJ}{IJ}

∴ tan(∠I) = \frac{3}{4}

The ratio  \frac{3}{4} represents the tangent of ∠I

7 0
3 years ago
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