Answer:
0.7223
Step-by-step explanation:
Given:
Probability of hitting, p = 0.226
Number of times player bats, n = 44
Now,
P (getting a least one hit) = 1 - P ( no hits )
also,
P( not hitting a hit in game )= qⁿ
where,
q = 1 - p
thus,
q = 1 - 0.226 = 0.774
Therefore,
P ( not hitting a hit in game ) = 0.774⁵ = 0.2777
Hence,
P ( getting a least one hit ) = 1 - P ( no hits )
or
P ( getting a least one hit ) = 1 - 0.2777
or
P ( getting a least one hit ) = 0.7223
Answer:
14.54
Step-by-step explanation:
In a <em>weighted average</em> a “weight” is associated to each value.
The weighted mean is computed the following way:
Suppose you want to calculate the weighted mean of the values
a1, a1, …, an
with weights
w1, w2,..., wn
Then
<em>Weighted mean</em> =(w1*a1+w2*a2+... +wn*an)/(w1+w2+...+wn)
In this case we have
a1= 12, w1 = 8
a2 = 13, w2 = 6
a3 = 17, w3 = 12
<u>Weighted mean </u>
(12*8+13*6+17*12)/(8+6+12) = 14.54 rounded to 2 decimal places.
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