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2 years ago

9

Frank wants to put fencing around the border of his rectangular lawn shown. He needs 16 feet of fencing. What is the length of t

he lawn?

2 answers:

pochemuha2 years ago

5 0

There are manny answers to this
6ft, 6ft, 2ft, 2ft
5ft, 5ft, 3ft, 3ft
7ft, 7ft, 1ft, 1ft

ahrayia [7]2 years ago

3 0

You do length times width times height

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Lera25 [3.4K]

Answer:

D) (0.59, 3.35)

Step-by-step explanation:

The inequality for the thickness of the metal bars is:

$|x-1.971| \leq1.38$

In order for this inequality to be true, the following conditions must be met:

$x-1.971 \leq1.38\\x-1.971 \geq -1.38$

The range of thickness "x" that fits the inequality is:

$x -1.971 \leq1.38\\x\leq 3.351\\x-1.971 \geq -1.38\\x\geq 0.591\\0.59\leq x\leq 3.35$

Thickness ranges from 0.59 to 3.35 units.

7 0

3 years ago

The same sentence can be spoken several different ways.<br> True or False?

Tamiku [17]

TRUE. I don't know for other languages, but in English you surely can do that.

6 0

3 years ago

Read 2 more answers

For each $n \in \mathbb{N}$, let $A_n = [n] \times [n]$. Define $B = \bigcup_{n \in \mathbb{N}} A_n$. Does $B = \mathbb{N} \time

andre [41]

Answer:

No, it is not.

Step-by-step explanation:

The set $C = \mathbb{N} \times \mathbb{N}$ contains every ordered pair of Natural numbers, while B only contains those pairs in which both values in each entry are the same. Therefore, C is a bigger set than B, but B is not equal to C because for example C contains $[1] \times [2]$ and B doesnt because 1 is not equal to 2.

4 0

2 years ago

Solve this problem in your notebook using all four steps. A board 60 in. long is cut into two parts so that the longer piece is

Viktor [21]

X = shorter piece
y = longer piece = 5x

shorter piece + longer piece = 60
x + 5x = 60
6x = 60
x = 60/6
x = 10 in. <== shorter piece

y = 5x
y = 5(10)
y = 50 in. <== longer piece

8 0

3 years ago

Twelve and three tenths more than five and thirteen thousandths of a number d is equal to fifteen and three hundred two thousand

Masja [62]

12 and 3/10 more than 5 and 13/1000 of d equals 15 and 302/1000
12 and 3/10+(5 and 13/1000 times d)=15 and 302/1000
convert to improper fractions
12 and 3/10=123/10
5 and 13/1000=5013/1000
15 and 302/1000=15302/1000

123/10+(5013/1000 times d)=15302/1000
subtract 123/10 from both sides
123/10=12300/1000
(15302-123000)/1000=2698/1000
5013/1000 times d=2698/1000
multiply both sides by 1000/5013 to clear fraction
d=2698/5013

7 0

2 years ago