Answer:
Alright well first off you start by converting everything to fractions, but decimals work better for me. So it would be 40.5 and 1.25, 40.5 being miles and the other gas. Divide 40.5 by 1.25, giving you 32.4
<u><em>His car get 32.4 miles per gallon</em></u>
20 / 27 is the probability that a student chosen randomly from the class passed the test or completed the homework.
<u>Step-by-step explanation:</u>
To find the probability that a student chosen randomly from the class passed the test or complete the homework :
Let us take,
- Event A ⇒ a student chosen randomly from the class passed the test
- Event B ⇒ a student chosen randomly from the class complete the homework
We need to find out P (A or B) which is given by the formula,
⇒ P (A or B) = P(A) + P(B) - P(A∪B)
<u>From the given table of data,</u>
- The total number of students in the class = 27 students.
- The no.of students passed the test ⇒ 15+3 = 18 students.
P(A) = No.of students passed / Total students in the class
P(A) ⇒ 18 / 27
- The no.of students completed the homework ⇒ 15+2 = 17 students.
P(B) = No.of students completed the homework / Total students in the class
P(B) ⇒ 17 / 27
- The no.of students who passes the test and completed the homework = 15 students.
P(A∪B) = No.of students both passes and completes the homework / Total
P(A∪B) ⇒ 15 / 27
Therefore, to find out the P (A or B) :
⇒ P(A) + P(B) - P(A∪B)
⇒ (18 / 27) + (17 / 27) - (15 / 27)
⇒ 20 / 27
∴ The P (A or B) is 20/27.
Answer:
yes
Step-by-step explanation:
expect when they chase me
Answer: La respuesta es cada 132 clientes
Lo que hice fue poner la parte de 33 y 44 sumándose entre si:
33+33=66+33=99+33=132 etc
44+44=88+44=132 etc
Y si te diste cuenta concuerdan los dos en 132
Espero que te sirva
Answer:
$57400
Step-by-step explanation:
Given data
P= $10,000
R= 6%
T= 30 years
Let us Assume the investment is compounded Anually
A= P(1+r)^t
A=10000(1+0.06)^30
A=10000(1.06)^30
A=10000*5.74
A=$57400
Hence the Final Amount after 30 years compounded anually is $57400
