Answer:
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Step-by-step explanation:
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Answer:
The answer is A.
Step-by-step explanation:
So we have the two equations:
To make a substitution of the second equation into the first equation, we need to isolate the <em>y </em>variable in the second equation. Thus:
Now, we can substitute this into the first equation. Therefore:
Answer=18 pages
Steven read 9 pages on Monday. If he needs to read DOUBLE that amount on Tuesday, then we need to take the number of pages he read on Monday and times it by 2.
9*2=18pages
Steven needs to read 18 pages on Tuesday.
**Remember that Double is the same as 'two times more', or 2x more...
Answer:
1486.67 or 1487.
Step-by-step explanation:
Find the average of those three things. Add 2,340 plus 470 plus 1650. You get 4460. Since you have three costs, divided 4460 by 3, which is 1486.6 repeating. Round to the nearest hundredth which is 1486.67. Hope this helps!
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
