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quester [9]
3 years ago
11

Jamal earns earns a year-end bonus of $32500 and puts it in 3 one-year investments that that pay $1579.50 in simple interest. Pa

rt is invested at 3%, part at 4%, and part at 6%. There is $9750 more invested at 6% than at 3%.
A. Create a system of equations that represents this ratio.

B. Find the amount invested at each rate.
Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

Fjjfhfuf

Step-by-step explanation:

Ffifuuf

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Triangle AOC intersects a circle with center O. side AO is 10 inches and the diameter of the circle is 12 inches. What is the le
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Answer:

AC=8inches

Step-by-step explanation:

It is given that triangle AOC intersects a circle with center O, side AO is 10 inches and the diameter of the circle is 12 inches, thus

OC is the radius of the circle and is equal to \frac{D}{2}=\frac{12}{2}=6 inches.

Now, From ΔAOC, using the Pythagoras theorem, we get

(OA)^{2}=(OC)^{2}+(AC)^{2}

⇒(10)^{2}=(6)^2+(AC)^2

⇒100=36+(AC)^2

⇒64=(AC)^2

⇒AC=8inches

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I need urgent help with this. please write out the working and the answer thank you
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1.         C = ⁵/₉F - 32
          9C = 9(⁵/₉F - 32)
          9C = 9(⁵/₉F) - 9(32)
          9C = 5F - 288
        - 5F  - 5F
  9C - 5F = -288
- 9C           - 9C
         -5F = -9C - 288
          -5           -5
            F = 1⁴/₅C + 57.6

2. H = w + \frac{50}{m^{2}}
    m^{2}(H) = m^{2}(\frac{50}{m^{2}})
    Hm^{2} = 50
    \frac{Hm^{2}}{H} = \frac{50}{H}
    m^{2} = \frac{50}{H}
    \sqrt{m^{2}} = \sqrt{\frac{50}{H}}
    m = \frac{\sqrt{50}}{\sqrt{H}}
    m = \frac{5\sqrt{2}}{\sqrt{H}}
    m = \frac{5\sqrt{2}}{\sqrt{H}} * \frac{\sqrt{H}}{\sqrt{H}}
    m = \frac{5\sqrt{2H}}{H}

3.                    A = 5 + 4√x
                     - 5  - 5
                  A - 5 = 4√x
              (A - 5)² = (4√x)²
    A² - 10A + 25 = 16x
             16             16
¹/₆A² - ⁵/₈A + 1⁹/₁₆ = x

4. A = \frac{b + c}{b}
    Ab = b(\frac{b + c}{b})
    Ab = b + c
    Ab - b = c
    b(A) - b(1) = c
    b(A - 1) = c
    \frac{b(A - 1)}{A - 1} = \frac{c}{A - 1}
    b = \frac{c}{A - 1}
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