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quester [9]
3 years ago
11

Jamal earns earns a year-end bonus of $32500 and puts it in 3 one-year investments that that pay $1579.50 in simple interest. Pa

rt is invested at 3%, part at 4%, and part at 6%. There is $9750 more invested at 6% than at 3%.
A. Create a system of equations that represents this ratio.

B. Find the amount invested at each rate.
Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

Fjjfhfuf

Step-by-step explanation:

Ffifuuf

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Liam buys a rosebush during the sale. If the original price was $30, how much does Liam pay?
kobusy [5.1K]

Answer:

Liam pays $24

Step-by-step explanation:

20% off = 20÷100= 1/5

1/5 × $30 = $6

$30 - $6 =$24

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Help me with this to and use pemdas or not
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First, parenthesis

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Next, exponents.

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Then, multiplication.

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After that, division.

63 ÷ 9 is 7

Finally, subtraction.

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Order these numbers from least to greatest. −270 , 16310 , −503 , −16.5
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A solution of nitric acid has a boiling point of 120 degrees Celsius. What is the boiling point of the solution in degrees Fahre
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A number, y, is equal to the difference of a larger number and 3. The same number is one-third of the sum of the larger number a
mariarad [96]

Answer:

The two equations are

y = x - 3 and

3y = x + 9

Step-by-step explanation:

The options are not well stated. I'll answer the question without the options but however, my answer will be a reflection of one of the given options.

Given:

2 statements

Required

Write equivalent of both statements as equations

Let the large number be represented by x.

From the first statement (y, is equal to the difference of a larger number and 3)

Difference means minus (-); so, this statement is represented as follows to give us the first equation:

y = x - 3

From the second statement (The same number is one-third of the sum of the larger number and 9).

This is also represented as follows to give us the second equation

y = ⅓(x + 9)

Multiply both sides by 3

3 * y = 3 * ⅓(x + 9)

3y = x + 9

So, the two equations are

y = x - 3 and

3y = x + 9

4 0
3 years ago
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