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Leni [432]
2 years ago
9

A professor has 7 books they are trying to arrange on a shelf. If the professor selects 3 books at a time, how many different ar

rangements of books can they come up with?
i got 210 but im not sure
Mathematics
1 answer:
nlexa [21]2 years ago
7 0

<em>The number of </em><em>different arrangements </em><em>of books is 210</em>

What is the formula for Permutation?

Permutation in mathematics can be calculated by using the formula

nPr = \frac{n!}{(n - r)!}

where

  • nPr = Permutation required
  • n = total number of objects = 7
  • r = number of objects selected = 3

nPr = \frac{7!}{(7-3)!}

nPr = \frac{5040}{24}

nPr = 210

Therefore, the required number of ways is 210

learn more about permutations here brainly.com/question/112112

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3 years ago
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What is the value of y ? <br> y=-2x+4?
sineoko [7]

Answer:

y = 4 + -2x

Step-by-step explanation:

Simplifying

y = -2x + 4

Reorder the terms:

y = 4 + -2x

Solving

y = 4 + -2x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

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3 years ago
This question is WORTH 15 POINTS
masha68 [24]
3x² - 33x - 180 = 0
3(x² - 11x - 60) = 0
3(x² - 15x + 4x - 60) = 0
3(x + 4)(x - 15) = 0
3(x - 4) = 0 or x - 15 = 0
3x - 12 = 0     <u>  + 15  + 15</u>
<u>    + 12 + 12</u>           x = 15
       <u>3x</u> = <u>12</u>
        3      4
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The answer is equal to H.15 and E. 4.
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3 years ago
Question 15 (5 points)<br> Find the angle between u = &lt;7, -2&gt; and v= (-1,2&gt;.
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Answer:

Approximately 2.3127 radians, which is approximately 132.51^{\circ}.

Step-by-step explanation:

Dot product between the two vectors:

\begin{aligned}& u\cdot v \\ =\; & 7 \times (-1) + (-2) \times 2 \\ =\; & (-11) \end{aligned}.

Magnitude of the two vectors:

\begin{aligned} \| u \| &= \sqrt{{7}^{2} + {(-2)}^{2}} \\ &= \sqrt{53} \end{aligned}.

\begin{aligned} \| v \| &= \sqrt{{(-1)}^{2} + {2}^{2}} \\ &= \sqrt{5} \end{aligned}.

Let \theta denote the angle between these two vectors. By the property of dot products:

\begin{aligned} \cos(\theta) &= \frac{u \cdot v}{\|u\| \, \| v \|} \\ &= \frac{(-11)}{(\sqrt{53})\, (\sqrt{5})} \\ &= \frac{(-11)}{\sqrt{265}}\end{aligned}.

Apply the inverse cosine function {\rm arccos} to find the value of this angle:

\begin{aligned} \theta &= \arccos\left(\frac{u \cdot v}{\| u \| \, \| v \|}\right) \\ &= \arccos\left(\frac{(-11)}{\sqrt{265}}\right) \\ & \approx \text{$2.3127$ radians} \\ &= 2.3127 \times \frac{180^{\circ}}{\pi} \\ &\approx 132.51^{\circ}\end{aligned}.

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