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Liula [17]
3 years ago
6

Help me solve this: 16-x=x

Mathematics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

8

Step-by-step explanation:

16 - x = x

16 = x + x

16 = 2x

16 ÷ 2 = x

8 = x

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Multiply. Express your answer in simplest form. 11 1/9 × 4 2/7
solmaris [256]

Answer:

47 13/21

Step-by-step explanation:

Given

11 1/9 x 4 2/7

First change the fractions to improper fractions.

We have ,

100/9 x 30/7

Multiply through

3000/63

Divide the numerator and denominator by 3

1000/21

47 13/21

5 0
2 years ago
Read 2 more answers
Solve for q using both equation 1 and 2 question in pic
galina1969 [7]

Answer:

p=1/8     q=3/4

Step-by-step explanation:

-2p+7q=5

-6p+35q=51/2

cancel out a variable

(-5)(-2p+7q=5)

-6p+35q=51/2

10p-35q=-25

-6p+35q=51/2  =

4p=1/2

4p/4=1/2  /4

p=1/8

substitute p=1/8 into one of the equation to find q

-2p+7q=5

-2(1/8)+7q=5

-1/4+7q=5

7q=5+1/4

7q=21/4

q= 21/4  /7

q=3/4

4 0
2 years ago
Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi
Ksivusya [100]

Given:

A line segment with initial point (–5, 3) and terminal point (1, –6).

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1 which defines the given line segment.

Solution:

Initial point is (–5, 3). So,

x(0)=-5,y(0)=3

Terminal point is (1, –6).

x(1)=1,y(1)=-6

Check which of the given set of parametric equations satisfy x(0)=-5,y(0)=3,x(1)=1,y(1)=-6.

Put t=1 in each set of parametric equations.

In option A,

y(1)=3-6(1)=3-6=-3\neq -6

So, option A is incorrect.

In option B,

y(1)=1-6(1)=1-6=-5\neq -6

So, option B is incorrect.

In option C,

y(1)=3-9(1)=3-9=-6

x(1)=-5+6(1)=-5+6=1

Put t=0, in this set of parametric equations.

x(0)=-5+6(0)=-5

y(0)=3-9(0)=3

So, option C is correct.

In option D,

y(1)=1-7(1)=1-7=-3\neq -6

x(1)=-5+8(1)=-5+8=3\neq 1

So, option D is incorrect.

8 0
2 years ago
What is the least common multiple of 12and9
Sergeu [11.5K]
I believe it's 36 :)
8 0
3 years ago
Read 2 more answers
13x-6y=22 x=y+6 find x and y
Vesna [10]
13x - 6y = 22
x - y = 6
6(x-y) = 6*6
6x - 6y = 36
subtract both the equations
13x - 6x -6y + 6y = -14
7x = -14
x = -2
13*-2 -6y=22
-26 -6y=22
-6y = 48
y = -8
answer: x = -2
y = -8
8 0
2 years ago
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