The value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
<h3>What is the rate of speed?</h3>
The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,
r=d/t
Here, (d) is the distance travelled by the object and (t) is time taken but the object to cover that distance.
The train traveled 1/3 of the distance at 30 mph and the remaining distance at 40 mph. Let <em>t</em> is the time the train has taken to travel and x is the distance it travelled. Thus,

After two hour a car left the same station traveled the first 3 hours at 35 mph and the remaining distance at 51 mph. Let <em>t</em> is the time the car has taken to travel and x is the distance it travelled. Thus,

As t is same, thus put the value of t in this equation,

Thus, the value of distance between the station and the city in terms of miles which train and car travelled at interval of 2 hours is 129.6 miles.
Learn more about the rate of speed here:
brainly.com/question/359790
#SPJ1
Answer:
Nine point two hundred two
Answer:
B. 40 cibic inches
Step-by-step explanation:
Hope it Help
9514 1404 393
Answer:
x = 12
perimeter = 124
Step-by-step explanation:
The midline RS is half the length of MN, so we have ...
2×RS = MN
2(x +3) = 5x -30
2x +6 = 5x -30
36 = 3x . . . . . . . . . add 30-2x
12 = x . . . . . . . . . . divide by 3
__
The length RS is then ...
RS = x +3 = 15
and the perimeter of QRS is ...
P(QRS) = QR +RS +SQ = 25 +15 +22 = 62
The perimeter of QRS is half the perimeter of MNP, so ...
P(MNP) = 2×P(QRS) = 2×62 = 124
The perimeter of ΔMNP = 124.