In simplest terms: (-5x-7)-(-4x-6)(−5x−7)−(−4x−6)
1 answer:
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The probability of a hand of 13 cards contains all 4 of one of the denominations, say Aces, is given by:
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
The answer is 0.0343.
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
The answer is 0.0343.