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natulia [17]
3 years ago
13

Compute the probability that a hand of 13 cards contains all 4 of at least 1 of the 13 denominations.answer: 0.0343

Mathematics
1 answer:
gogolik [260]3 years ago
5 0
The probability of a hand of 13 cards contains all 4 of one of the denominations, say Aces, is given by:
\frac{4C4\times48C9}{52C13}=0.00264106
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
0.00264106\times13=0.0343
The answer is 0.0343.
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