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sergij07 [2.7K]

3 years ago

8

What do the letters CLU stand for in relation to an insurance agent? A. Certified Legal Underwriter B. Chartered Legal Underwrit

er C. Chartered Life Underwriter D. Certified Licensed Underwriter

1 answer:

Sophie [7]3 years ago

7 0

The correct answer is c.) c<span>hartered life underwriter.</span>

You might be interested in

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and st

SashulF [63]

Answer:

0.7233

Step-by-step explanation:

We want to find the area between the z-scores z=-0.95 and z=1.25.

We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.

For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.

This gives P(z<-0.95)=0.1711

Similarly the area to the left of z=1.25 is

P(z<1.25)=0.8944

Now the area between the two z-scores is

P(-0.25<z<1.25)=0.8944-0.1711=0.7233

7 0

3 years ago

How do you write the equation of a line (in slope intercept form) with three given points?

Mrrafil [7]

With even just two points, you can find the equation of a line in slope-intercept form.

Slope-intercept form: $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept

<u>1) Solve for the slope (</u> $m$ <u>)</u>

The equation to solve for the slope is $m=\frac{y_2-y_1}{x_2-x_1}$ when the two points are $(x_1,y_1)$ and $(x_2,y_2)$ . Plug the coordinates of these points into the equation and solve for $m$ .

Then, plug $m$ into $y=mx+b$ .

<u>1) Solve for the y-intercept (</u> $b$ <u>)</u>

Then, take any of the given points and plug it into $y=mx+b$ along with the slope. Isolate $b$ to get the y-intercept. Then, plug both m and b back into $y=mx+b$ to get your final equation.

I hope this helps!

3 0

3 years ago

Read 2 more answers

I don't understand what it's asking

Arlecino [84]

Answer:

bdbdjsjsbsbsbbshssbdjdjdjsjhshshdjdd

4 0

2 years ago

Read 2 more answers

Plz show work and solve quick please need help!!!!!

Simora [160]

Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

$\sf A=lw$

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

$\sf A=(56)(27)$

$\sf A=1512cm^2$

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

$\sf 82.8-28=54.8\? cm$

Calculate the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(27)(54.8)$

$\sf A=739.8\?cm^2$

We have two of these triangles.

$\sf 739.8\times 2=1479.6\? cm^2$

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

$\sf 81.2-27=54.2\?cm$

Now find the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(56)(54.2)$

$\sf A=1517.6\? cm^2$

We have two of these triangles.

$\sf 1517.6\times 2=3035.2\?cm^2$

Add all the areas together:

$\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}$

7 0

3 years ago

Help pleasee!!!!!!!!!!!!!!!!!!

defon

Answer:

76 because if the two lines are parallel then x = 76

hope this helps and brainliest please

8 0

3 years ago