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Semmy [17]
2 years ago
14

May I please receive help?

Mathematics
1 answer:
QveST [7]2 years ago
8 0

Answer:

a = 19.6 (rounded to the nearest tenth)

Step-by-step explanation:

a^2 + b^2 = c^2

Hypotenuse - 35 m, Legs - 29 m, x

a^2 +29^2 = 35^2

a^2 + 841 = 1225

Subtract 841 from both sides

a^2 = 384

Square root both sides

√a^2 = √384

a = 19.595

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HELP!
artcher [175]

Answer:

B.Obtuse

as shown in the pictures that you put the angel is obtuse

6 0
3 years ago
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,
tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}

Mean is represented by the following expression:

\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}\text{Mean}=\frac{84}{10}=8.4

Population variance formula looks like this:

\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}

Then, substituting:

\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}

For the standard deviation:

\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}

5 0
1 year ago
What does x equal please help
nekit [7.7K]

Answer: 5 1/2 (5.5)

Step-by-step explanation:

add 4 2/3 to 5/6

3 0
3 years ago
Use quadratics---------------
Elza [17]
A square's area is the square of the sides 

square area= side²
side=\sqrt{96x^5} 

side=\sqrt{2(2)(2)(2)(3)x^2(x)}
side=4x^2 \sqrt{3x}

OR we can divide it 
    |_ 96x^5
 x²|_ 96x^3
 x⁴|_ 96x
4x⁴|_ 3x

5 0
4 years ago
When factored completely, what are the factors of 4x^2-16 ?
Semmy [17]
Use:a^2-b^2=(a-b)(a+b)\\\\4x^2-16=4(x^2-4)=4(x^2-2^2)=\boxed{4(x-2)(x+2)}
8 0
3 years ago
Read 2 more answers
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