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3 years ago

13

What is the slope on (3,5) and (-3,-5)

1 answer:

xxMikexx [17]3 years ago

5 0

6/10 or if you need the simplest form 3/5

You might be interested in

There are 276 nickels. How many whole dollars can be made from this and with how many nickels left over?

cupoosta [38]

1 nickel = 5 cents
1 dollar = 20 nickels

You can make 13 dollars plus 16 nickels left over

20 * 13 = 260
then 260 + 16 = 276

6 0

3 years ago

A 60-kilogram person stands on a compression spring. The spring constant is 2500 Newtons per meter What is the displacement of t

Mademuasel [1]

The answer is 0.024m

60-kilogram divided by 2500 Newtons per meter or 60/2500 is 0.024

6 0

3 years ago

How do you write one million, twelve thousand, sixty widgets in standard form

bekas [8.4K]

One million = 1000000
Twelve thousand = 12000
Sixty = 60

One million, twelve thousand and sixty = 1 012 060

Standard form is given by A × 10ⁿ
Where A is a number in unit and 'n' is an integer

1 012 060 = 1.012060 × 10⁶

4 0

3 years ago

An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 1.6

nexus9112 [7]

Answer:

n=1705

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=1.6)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{1.6}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 2.58$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{2.58(1.6)}{0.1})^2 =1704.03$

And if we round up the answer we see that the value of n to ensure the margin of error required $\pm=0.1$ mm is n=1705.

6 0

3 years ago

We are given that a force of 40 N is exerted at an angle of 39°. Therefore, the force vector F can be represented as the hypoten

Deffense [45]

The answer is 0 degrees

6 0

3 years ago