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Blizzard [7]
3 years ago
11

Identify the 16th term of a geometric sequence where a1 = 4 and a8 = -8,748.. . -172,186,884. -57,395,628. 57,395,628. 172,186,8

84.
Mathematics
2 answers:
zvonat [6]3 years ago
8 0

Answer:

−57,395,628

Step-by-step explanation:

stiv31 [10]3 years ago
4 0
First, determine the common ratio by the equation,
                                an = a1 x r^(n - 1)
Substituting the values,
                           -8748 = 4 x r^(8 - 1) 
The value of r is -3. By the same equation, the 16th term is,
                                 a16 = 4 x (-3)^(16 - 1)
                                 a16 = -57,395,628
Thus, the answer is the second choice. 
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