If it was one year it would be 2200 and you just keep adding 200 for each year.
        
             
        
        
        
Answer:
B
Step-by-step explanation:
No solutions 
 
        
                    
             
        
        
        
Sum of n terms  = a1  (r^n-1/ (r-1)
Sum of first one = 3 * (4^5 - 1) / 3  =  1023
  ..           2nd =  5 * (6^2 - 1) / 5 =  35
   ..            3rd = 5 ^4 - 1 / 4 =  156
   ..            4th =  4 * (5^4 - 1) / 4 = 624
So in increasing order its   2nd, 3rd, 4th and first.
        
             
        
        
        
Yes it correct.............