2+4z-18
change it so it's an equation
2+4z-18=0
then get 4z alone on one side by subtracting 4z from both sides
2-18=-4z
-16= -4z
divide both sides by -4
a negative divided by a negative becomes positive
4 =z
plug it in
2+4(4)-18
4x4 is 16
2+16-18=0
0=0
the same can be done for the second one 2+k-8
make it 2+k-8=0
move the k to get it alone so subtract k from both sides
2-8=-1k
-6 = -1K
you can divide by K to make K=6
plug in 2+6-8=0
0=0
Let y = 0 to find the zeros.
We can now split the middle term into factors of 6 that add up to 5.
Group the first two terms, and group the last two terms, and factorise.
Group like terms.
Now, we know that in order for a zero to occur, either x + 3 = 0 or x + 2 = 0.
Hence, x = -3 and -2 are the zeros in this quadratic.
Step-by-step explanation:
it is really simple.
first of all, when 2 lines intersect (and we are talking straight lines, otherwise they are not lines in the mathematical sense), the angles created are the same in both sides of the lines (just left-right mirrored).
and secondly, the sum of all angles around a single point in one side of a line must be 180°, as the line can be considered the diameter of a circle, the point the center is the circle, and all the angles on one side are a half-circle.
so,
angle 3 = 37°
that means
angle 1 = 37° too
angle 2 is supplementary to e.g angle 3 (that means they both add up to 180° as explained above).
angle 2 = 180 - 37 = 143°
and angle 4 = 143° too
Answer:
x = 2 if you are trying to solve for x
Step-by-step explanation:
Use the formula (y2-y1)/(x2-x1) from the coordinates
(3-9)/(8--7)
-6/15 reduce to get
-2/5 is the slope.