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Neporo4naja [7]
4 years ago
6

Draw two isosceles triangles, ∆ABC and ∆ADC with common base AC . Vertexes B and D are in the opposite semi-planes determined by

AC . Draw the line segment BD . Prove: AC ⊥ BD
Mathematics
2 answers:
Alexus [3.1K]4 years ago
8 0

Answer:

7yer87rhg

Step-by-step explanation:

qaws [65]4 years ago
5 0
Statement                                               Reason

<span>∆ABC and ∆ADC are isosceles              Given

Segment AC is a common base
to </span><span>∆ABC and ∆ADC                                Given

Let K be the midpoint of the base
of </span><span>segment AC, then BK is the
perpendicular bisector of segment         </span><span>perpendicular bisector of isosceles AC.                                                         triangle property.</span>

Also, <span>DK is the perpendicular
bisector of segment AC.                        </span><span>perpendicular bisector of isosceles                                                                    triangle property.</span>
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