You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.
If the 
coefficient is 1, i.e. the equation is written like 
, then you can say the following about the coefficients b and c:
is the opposite of the sum of the roots
is the multiplication of the roots.
So, for example, if we want an equation whose roots are 4 and -2, we have:
So, the equation is 
If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:
And so the equation is
In order to have integer coefficients, you can multiply both sides of the equation by 8:
If we have
y = 6x + 1 and x - y = 11, we can take advantage of y - y = 0 as follows:
Subtract x from both sides of the 2nd equation:
-y = 11 - x
Now combine
y = 6x + 1
-y = 11 - x
--------------
0 = 5x + 12. Solving for x, x = -12/5. Using the equation above, find y:
-y = 11 - x
= 11 - (-12/5)
= 55/5 + 12/5 = 67/5
Then the solution is (-12.5, 67/5).
Answer:
23.83
Step-by-step explanation:
Answer:
1.the area of a circle is Pie/3.14 times radius of the circle squared
2.and if your given the diamter of the circle cut the number in half and it will give you the radious.
Step-by-step explanation:
