The number of mole of carbon dioxide, CO₂ formed from the reaction is 0.0632 mole.
<h3>How to determine the mole of NaHCO₃</h3>
- Molarity of NaHCO₃ = 2 M
- Volume = 31.6 mL = 31.6 / 1000 = 0.0316 M
- Mole of NaHCO₃ =?
Mole = Molarity x Volume
Mole of NaHCO₃ = 2 × 0.0316
Mole of NaHCO₃ = 0.0632 mole
<h3>How to determine the mole of CO₂</h3>
NaHCO₃ + HCl —> CO₂ + H₂O + NaCl
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.
Therefore,
0.0632 mole of NaHCO₃ will also react to produce 0.0632 mole of CO₂.
Thus, 0.0632 mole of CO₂ was obtained from the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
Answer:
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Atomic radii INCREASES when going DOWN a group because of more energy levels and DECREASES going ACROSS a group because of the increasing positive charge of the nucleus pulling in on the electrons.
Answer:
m<TQS = 137, m<RQS = 43
Explanation:
TQS RQS
(6x+20) + (2x+4) = 180
combine like terms:
8x + 24 = 180
subtract 24 from both sides:
8x = 156
divide 8:
x = 19.5
Plugin x:
<u>TQS</u>
6(19.5) +20 =
117 + 20 = 137
m<TQS = 137
<u>RQS</u>
2(19.5) + 4 =
39 + 4 = 43
m<RQS = 43
