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Fudgin [204]
2 years ago
5

Which of the following are correct descriptions of the compositions of earth's different internal layers?.

SAT
1 answer:
lisabon 2012 [21]2 years ago
7 0

The answer choice which is the correct description of the compositions of earth's different internal layers is:

  • The Crust
  • The Mantle
  • The Core

<h3>The Earth</h3>

The earth is made up of various layers and the composition of the internal layers can be classified into the crust, mantle and core.

Each different layer has distinct features and characteristics which makes them unique and are important to preserve the Earth's core.

Read more about earth's internal layers here:
brainly.com/question/2673884

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Why is it not always necessary to include a subject pronoun
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Because the ending of the conjugated verb “tells” us the subject.
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A pendulum is made by tying a 75 g ball to a 130-cm-long string. the ball is pulled 5.0∘ to the side and released.
Maslowich

The ball’s speed and direction at the lowest point of trajectory are; 3.1 m/s and swing to the same angle on the other side

<h3>What is the speed at the lowest point?</h3>

We will assume that all of the motion will transfer to Kinetic Energy at the lowest point. Now, the difference in height will be;

Δh = (130 – 130*cos °5) = 0.49 cm

The change in PE is;

ΔP.E = mgΔh

ΔP.E = 9.8m/s² × 0.75kg × 0.049 m

ΔP.E = 0.36015 J

Formula for kinetic energy is;

K.E = ¹/₂*m*v²

From conservation of energy;

K.E = P.E

Thus;

¹/₂* 0.075 * v² = 0.36015

v = √[(0.36015 * 2)/0.075]

v = 3.1 m/s

Thus, the pendulum will swing to the same angle on the other side.

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6 0
2 years ago
A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the
mars1129 [50]

Answer:

Answer:

Stabilizer with area = 14 cm².

Step-by-step explanation:

Area of the wing = 101.25 cm²

Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.

1/6 of the area of wing = \frac{1}{6} \times 101.25 = 16.87561×101.25=16.875

1/8 of the area of wing = \frac{1}{8} \times 101.25 = 12.65681×101.25=12.656

This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²

Therefore, area of a good stabilizer design from the given options would be 14 cm²

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3 years ago
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