Please quickly answer number 6 will give brainliest
2 answers:
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Answer:
The expected value of the safe bet equal $0
Step-by-step explanation:
If
is a finite numeric sample space and
for k=1, 2,..., n
is its probability distribution, then the expected value of the distribution is defined as
What is the expected value of the safe bet?
In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is
S = {100,-100}
Since the coin is supposed to be fair,
P(X=100)=0.5
P(X=-100)=0.5
and the expected value is
E(X) = 100*0.5 - 100*0.5 = 0
In a rhombus, the diagonals meet at right-angles, and they bisect each other, namely they cut each other in half, check the picture below.
thus we can use the pythagorean theorem to get one side, keeping in mind that, slanted as it may be, all sides in a rhombus are equal in length.
thus we can use the pythagorean theorem to get one side, keeping in mind that, slanted as it may be, all sides in a rhombus are equal in length.
Answer:
$4785.68
Step-by-step explanation:
Original amount: <u>$</u><u>4</u><u>2</u><u>3</u><u>0</u>
Interest for 1 year: <u>4</u><u>.</u><u>2</u><u>%</u>
<em>First year;</em>
<em>S</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em><em> </em><em>y</em><em>e</em><em>a</em><em>r</em><em>;</em>
<em>T</em><em>h</em><em>i</em><em>r</em><em>d</em><em> </em><em>y</em><em>e</em><em>a</em><em>r</em><em> </em><em>(</em><em>t</em><em>o</em><em>t</em><em>a</em><em>l</em><em> </em><em>b</em><em>a</em><em>l</em><em>a</em><em>n</em><em>c</em><em>e</em><em> </em><em>a</em><em>f</em><em>t</em><em>e</em><em>r</em><em> </em><em>3</em><em> </em><em>y</em><em>e</em><em>a</em><em>r</em><em>s</em><em>)</em><em>;</em>
Round the number;
<em><u>$4785.68</u></em>
YOUR ANSWER hope this helps :))