Step-by-step explanation:
the solutions for a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = -4
c = k
x = (4 ± sqrt(16 - 4k))/2 = 2 ± sqrt(4 - k)
x1 = 2 + sqrt(4 - k)
x2 = 2 - sqrt (4 - k)
x1 = 2 + x2
2 + sqrt(4 - k) = 2 + 2 - sqrt(4 - k)
2×sqrt(4 - k) = 2
sqrt(4 - k) = 1
4 - k = 1
k = 4 - 1 = 3
x1 = 3
x2 = 1
So in order to add the fractions together you need to first find a common denominator. For the very first problem you can use 63 as a denominator because 7*9=63. Now for the numerator. So you have 4/7 and 8/9. We just multiplied 7 by 9 so now we need to do that for 4 also. 4*9=36. Now we have 36/63. For 8/9 we multiply 8 by 7 to get 56. Now we have 36/63 + 56/63. Once you add those together you simplify your answer.
Simplified: -6m-6
Factored: 6(m+1)
When adding two together multiply:
log2 6 + log2 2 = log2(6*2) = log2 12
When you subtract 2 logs, divide:
So you have log2 12 / log2 8
Rewrite as log2 12/8
Simplify to get log2 3/2
The answer is C.
Answer:
The question
after change the mixed number to improper & using KCF will become : 
Option B is correct option.
Step-by-step explanation:
We need to change the mixed number to improper & use KCF to rewrite the question.
The expression is: 
First converting mixed fraction into improper fraction
Multiply whole number with the denominator i,e (3*2=6) now add the numerator i.e (6+1) = 7/2
Solving:

Using KCF
KCF stands fro Keep it, Change it, Flip it.
It is used when division sign is converted to multiplication the term (1/3) is reversed to (3/1)
So, our expression will be

So, The question
after change the mixed number to improper & using KCF will become : 
Option B is correct option.