Write an equation of a line parallel to line EF below in slope-intercept form that passes through the point (2, 6).
1 answer:
Answer:
y = -⅔x + ²²/₃
Step-by-step explanation:
1. Calculate the slope of EF
Assume E is at (-2, 5) and F is at (1, 3).
m₁ = (y₂ - y₁)/(x₂ - x₁) = (3 - 5)/(1 -(-2)) = -⅔
2. Calculate the slope of the parallel line
m₂ = m₁ = -⅔
3. Calculate its y-intercept
y = mx + b
6 =-⅔(2) + b
Simplify
6 = -⁴/₃ + b
Add ⁴/₃ to each side
b = 6 + ⁴/₃ = ¹⁸/₃ + ⁴/₃ = ²²/₃
The y-intercept is at (0,²²/₃).
4. Write the equation for the line
y = -⅔x + ²²/₃
The diagram shows EF in red. The parallel line in black passes through (2, 6) with a y-intercept at (0,²²/₃).
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Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221