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hodyreva [135]
2 years ago
5

HELLLLLLLLLLLLLPPPPPPPPPP

Mathematics
2 answers:
Liula [17]2 years ago
6 0

Answer:

B.

Step-by-step explanation:

mark me brainliest pl

lawyer [7]2 years ago
3 0

The first option. 100% correct.

a_n = 3\cdot a_{n-1}\\\\a_1 = 7\\\\a_2 = 3 a_{2-1} =3a_1 = 3(7) =21\\\\a_3 = 3 a_{3-1} =3a_2 = 3(21) = 63 \\\\a_4 = 3 a_{4-1} = 3 a_3 = 3 (63)=189\\\\7,21,63,189,......

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*Need help asap*
aleksandr82 [10.1K]

One example would be x to the power of 1/3

which we would write as x^(1/3) for shorthand

It converts to "cube root of x".

----------------

The general rule is

x^{1/n} = \sqrt[n]{x}

if the font is too small, then the formula reads x^(1/n) is equal to square root x, with a small little n just above and to the left of the square root. This is known as the nth root of x.

Based on that general formula, we can say something like

x^{1/4} = \sqrt[4]{x}

(x to the 1/4th power is equal to fourth root of x)

note: you can replace x with any algebraic expression you want

7 0
2 years ago
1. A linear function can be represented by the equation y = 7x - 4. Identify the slope and y-intercept.
Leto [7]

Hello!

Remember y=mx+b.

m is the slope and b is the y intercept.

So

the slope is 7 and the y intercept is 4.

Hope this helps!

~Just a felicitous teen

#CarryOnLearning

SIlentNature

8 0
2 years ago
Read 2 more answers
Longhorn Corporation provides low-cost food delivery services to senior citizens. At the end of the year on December 31, 2021, t
julsineya [31]

The statement of stockholders’ equity for Longhorn Corporation is: $62,800

                                                           

<h3> Statement of stockholders’ equity</h3>

                        Common stock   Retained earning Total stakeholder equity

Beginning balance           $36,000    $17,400        $53,400              

Issuance of common stock  $4,000        -                $4,000

Add net income                          -        $5,400            $5,400

[65,700-(53,000+2,200+5,100)]

Ending balance                      $40,000    $22,800      $62,800

Therefore the statement of stockholders’ equity for Longhorn Corporation is: $62,800.

Learn more about  Statement of stockholders’ equity here:brainly.com/question/13950797

#SPJ1

4 0
2 years ago
Over the course of a year, a company goes from 115 employees to 124 employees.
just olya [345]

An equation that could be used to find the percent change, p, in the number of employees is:

\begin{array}{l}{p=\frac{\text {change in number of employees}}{\text {previous count}} \times 100} \\\\ {\mathrm{p}=\frac{9}{115} \times 100}\end{array}

<h3><u>Solution:</u></h3>

Given that, Over the course of a year, a company goes from 115 employees to 124 employees.

Given that "p" represents the percent change

Percentage change equals the change in value divided by the absolute value of the original value, multiplied by 100.

\text { Percent change "p" }=\frac{\text { change in number of employees }}{\text { previous count }} \times 100

Change in number of employees = present count – previous count

So, change in number of employees = 124 – 115 = 9

\begin{array}{l}{p=\frac{9}{115} \times 100} \\\\ {p=\frac{9}{23} \times 20} \\\\ {p=\frac{180}{23}=7.82}\end{array}

The equation that is used to find the percent change is:

\begin{array}{l}{\mathrm{p}=\frac{\text { change in number of employees }}{\text { previous count }} \times 100} \\\\ {\mathrm{p}=\frac{9}{115} \times 100}\end{array}

7 0
2 years ago
a coin will be tossed 10 times. Find the chance that there will be exactly 2 heads among the first five tosses and exactly 4 hea
777dan777 [17]

Answer:

The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.

Step-by-step explanation:

To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.

Both heads and tails have an individual probability p=0.5.

Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.

The probability that k heads are in the sample is:

P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{5}{k}\cdot0.5^k\cdot0.5^{5-k}

Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:

P(x=2)=\dbinom{5}{2}\cdot0.5^{2}\cdot0.5^{3}=10\cdot0.25\cdot0.125=0.3125\\\\\\

For the last five tosses, the probability that are exactly 4 heads is:

P(x=4)=\dbinom{5}{4}\cdot0.5^{4}\cdot0.5^{1}=5\cdot0.0625\cdot0.5=0.1563\\\\\\

Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:

P(H_1=2;H_2=4)=P(H_1=2)\cdot P(H_2=4)=0.3125\cdot0.1563=0.0488

7 0
3 years ago
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