Answer:
2.94 × 10²⁰ N/C
Explanation:
Given that:
The nucleus of "Lead-208 has 82 protons,
with a radius (r) 6.34×10-15 m, &
each electric charge has a value of 1.60218 × 10^-19 C
∴ The formula for calculating an electrical field at the surface of the nucleus is:
Substituting our values into the equation above, we have;
E = 
E = 2.93870499×10²⁰ N/C
E ≅ 2.94 × 10²⁰ N/C
a) volume in cm³ = 20 × 42 × 42 = 35280 cm³
b) volume in m³ = 0.2 × 0.42 × 0.42 = 0.03528 m³
c) volume in ml³ = 200 × 420 × 420 = 35280000 ml³
d) volume in litres = 0.02 × 0.042 × 0.042 = 0.00003528 l³
e) Density = Mass / Volume
Mass = Volume × density
= 0.00003528 × 1
= 0.00003528 × 1000
= 0.03528 grams
f) Mass in kilo gram = 0.00003528 kg
Answer:
In an interval of 5 minutes, ER has ribosomes attached to it which makes proteins synthesizing in the lumen of the endoplasmic reticulum incorporates proteins in the small transport vesicles.
These vesicles transport and fused to the Golgi bodies where proteins modified which can be seen in 15 minutes in the figure. Then modified proteins are transported from the cell cytosol with the help of secretory vesicle to the extracellular matrix and to the required organs.
