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2 years ago

12

Please explain part i

2 answers:

marshall27 [118]2 years ago

7 0

Answer:

300

Step-by-step explanation:

The red portion is marked with a small square; that means it is a 90° section. It is 1/4 of the whole circle. They also said 75 kids chose red. If 1/4 of the circle represents 75 kids, then the whole entire circle would represent 75+75+75+75 kids or 4(75) kids, which is 300 kids.

Luda [366]2 years ago

5 0

I guess u just have to give them another color bc that’s what it’s asking for

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you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

In ΔNOP, the measure of ∠P=90°, the measure of ∠N=59°, and PN = 7.4 feet. Find the length of OP to the nearest tenth of a foot.

lina2011 [118]

Answer:

12.3 feet.

Step-by-step explanation:

As we are given that $\triangle NOP$ is an right angled triangle.

$\angle P = 90 ^\circ \\\angle N = 59 ^\circ\\Side\ PN = 7.4 \text{ feet}$

And we have to find out the value of side OP to the nearest tenth of a foot by rounding off the value as seen in the attached figure as well.

By using Trigonometric functions in a right angled $\triangle$ , we know that:

$tan \theta = \frac{Perpendicular}{Base}$

Here, $\theta$ is $\angle N$ , Perpendicular is side <em>OP</em> and Base is side <em>PN</em>.

So, $tan 59^\circ = \frac{OP}{PN}$

$\Rightarrow OP = PN \times tan59^\circ$

Putting the values of <em>PN </em>and $tan59^\circ$ .

$OP = 1.66 \times 7.4\\\Rightarrow OP = 12.3 ft$

Hence, the value of <em>OP </em>is $12.3\ feet$ .

8 0

3 years ago

In ΔABC shown below, ∠BAC is congruent to ∠BCA: Triangle ABC, where angles A and C are congruent Given: Base ∠BAC and ∠ACB are c

Morgarella [4.7K]

1. Definition of bisector
2. ASA congruence theorem or ASA Postulate

6 0

3 years ago

Read 2 more answers

What is the simplest form for 15:25

vazorg [7]

Answer:

3/5

Step-by-step explanation:

Both can be divided by 5. So, 15 divided by 5 is 3, and 25 divided by 5 is 5! Hoped this helped :)

3 0

2 years ago

Please help me it’s almost due

Serhud [2]

I believe the answer is C

7 0

3 years ago