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vlabodo [156]
3 years ago
5

Please help with 1 and 2

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

1. B. a=14, b=2

2. D. a=1, b=1.4

Step-by-step explanation:

The exponential growth function can be represented as

y=a\cdot b^x,

where b is the growth factor.

1. When the function has equation

g(x)=14\cdot 2^x,

then

a=14,\\ \\b=2

The initial amount is the value of the function at x=0:

g(0)=14\cdot 2^0=14\cdot 1=14

The growth factor is b=2

2. When the function has equation

f(t)=1.4^t,

then

a=1,\\ \\b=1.4

The initial amount is the value of the function at t=0:

f(0)=1.4^0=1

The growth factor is b=1.4

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<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.

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3 years ago
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a> everybody
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2 years ago
What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


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You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

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3 years ago
31/9 as a mix number
Nataly [62]
3 and 4/9 would be the answer to this.
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