Answer:
perpendicular line through a point on a line
Step-by-step explanation:
The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.
The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)
So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.
Segment GH is perpendicular to AB through point C (on AB).
The given identity tells you ...
.. (sum of numbers) * (sum of squares - product) = (sum of cubes)
Substituting the given information, you have
.. (sum of numbers) * (29 -10) = 133
Then you can divide by (29 -10) to get
.. sum of numbers = 133/19 = 7
The sum of the two numbers is 7.
−<span>3<span>(<span><span>4a</span>−<span>5b</span></span>)</span></span><span>=<span><span>(<span>−3</span>)</span><span>(<span><span>4a</span>+<span>−<span>5b</span></span></span>)</span></span></span><span>=<span><span><span>(<span>−3</span>)</span><span>(<span>4a</span>)</span></span>+<span><span>(<span>−3</span>)</span><span>(<span>−<span>5b</span></span>)</span></span></span></span><span>=<span><span>−<span>12a</span></span>+<span>15<span>b</span></span></span></span>
Answer:
each jewel was 3 $
Step-by-step explanation:
divide 108.00/36= 3
Let us start dividing 30 by small prime numbers in increasing order .
the smallest prime number we use is 2
Let's divide 30 by 2 quotient is 15
so we get : 30 = 2* 15
15 is not a prime number , it can be factorized further .
now we start dividing 15
2 can not divide 15 so we move to next prime number that is 3
can 3 divide 15? yes .
we get a quotient 5
so 30 is now : 2* 15 = 2* 3*5
now we have to work on 5 but 5 is a prime number so we stop here .
the prime factorization of 30 is : 2* 3* 5
Answer : 2 *3*5
