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Y_Kistochka [10]
2 years ago
5

If ABC is right-angled at B , AB = 3 cm. , BC = 4 cm. , then the length of the median from B is​

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
6 0
Therefore, the length of the median from B is 5/2 cm.

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Translate and solve using proportions: What number is 30% of 60
balandron [24]

Answer: 18

Step-by-step explanation:

The question is asked to know 30% of 60, we get

60 x 30% = 60 x 0.3 = 18

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3 years ago
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An equation is shown 5 x + 3x equals 5x + 15 / 2 what value of 3 x makes this equation true
Ipatiy [6.2K]
3x would have to be 15/2.

Since we have that 5x+3x=5x+15/2, the only pieces that are different are the 3x and the 15/2.  This gives us the equation

3x=15/2

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4 years ago
Which linear inequality is represented by the graph?
aalyn [17]

Answer:

y ≤ 1/3 x - 1.3.

Step-by-step explanation:

First find the equation of the line:

The slope = (-0.3 - (-1.3) / (3 - 0).

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b is the y-intercept which is the value of y when x  = 0 . We see that it is -1.3 ( from the point 0, -1.3).

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blagie [28]

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Step-by-step explanation:

6 0
3 years ago
If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func
olga2289 [7]

Answer:

a. C(1,000) = 420,491.11

b. c(1,000) = 420.49

c. dC/dx(1,000) = 429.72

d. x = 900

e. c(900) = 420

Step-by-step explanation:

We have a cost function for x units written as:

C(x) = 54,000 + 240x + 4x^{3/2}

a. The total cost for x=1000 units is:

C(1,000) = 54,000 + 240(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=54,000+240,000+4\cdot  31,622.78\\\\C(1,000)=54,000+240,000+ 126,491.11 \\\\C(1,000)=  420,491.11

b. The average cost c(x) can be calculated dividing the total cost by the amount of units:

c(1,000)=\dfrac{C(1,000)}{1,000}=\dfrac{ 420,491.11 }{1,000}= 420.49

c. The marginal cost can be calculated as the first derivative of the cost function:

\dfrac{dC}{dx}=240(1)+4(3/2)x^{3/2-1}=240+6x^{1/2}\\\\\\\dfrac{dC}{dx}(1,000)=240+6(1,000)^{1/2}=240+6\cdot 31.62=429.72

d. This value for x, that minimizes the average cost, happens when the first derivative of the average cost is equal to 0.

c(x)=\dfrac{C(x)}{x}=\dfrac{54,000+240x+4x^{3/2}}{x}=54,000x^{-1}+240+4x^{1/2}\\\\\\ \dfrac{dc}{dx}=54,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\\\\dfrac{dc}{dx}=-54,000x^{-2}+2x^{-1/2}=0\\\\\\2x^{-1/2}=54,000x^{-2}\\\\\\x^{-1/2+2}=54,000/2=27,000\\\\\\x^{3/2}=27,000\\\\\\x=27,000^{2/3}=900

e. The minimum average cost is:

c(900)=54,000(900)^{-1}+240+4(900)^{1/2}\\\\c(900)=60+240+120\\\\c(900)=420

7 0
3 years ago
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