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emmainna [20.7K]
3 years ago
15

How you feel sometimes when you critique your friend

SAT
1 answer:
n200080 [17]3 years ago
5 0
Good because I know I am giving them good pointers, or feedback on whatever the situation may be.
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I WILL GIVE THE CORRECT PERSON BRAINIEST
attashe74 [19]

Answer: C.) The actions of consumers in response to changes in price.

Explanation:

The Law of Demand states that as the price of a service/product decreases, the demand will increase and vice versa. Therefore, it doesn't necessarily related to the producer's response, but the consumer's. And since the consumer isn't producing, they are not in direct contact with the production costs.

I hope this helped !

Good luck <3

5 0
3 years ago
Read 2 more answers
eva's mother describes her as a mildly active child. she also feels that eva's mood is marginally negative. according to chess a
slamgirl [31]

Answer:

hynntntbtnt

Explanation:

klltlrlrlrlellsliwlrkkwkrkriirirktktirl4l4ll4

7 0
2 years ago
suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a
saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

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3 0
3 years ago
Read 2 more answers
A shot putter releases the shot some distance above the level ground with a velocity of 12. 0 m/s, 51. 0∘ above the horizontal.
KIM [24]

A) The x­-component of the shot's acceleration while in flight is; aₓ = 0 m/s²

B) The y-component of the shot's acceleration while in flight is;

a_y = -9.8 m/s²

C) The x­-component of the shot's velocity while in flight is; vₓ = 7.55 m/s

D) The y-component of the shot's velocity while in flight is;

a_y = 9.32 m/s

<h3>Projectile motion</h3>

A) The x-component of the shot's acceleration while in flight?

aₓ = 0 m/s²

B) Since the object is thrown vertically, it means that it is against gravity and as such acceleration due to gravity will be negative,

Thus, the y-component of the shot's acceleration while in flight is;

a_y = -9.8 m/s²

C) The x-component of the shot's velocity at the beginning of its trajectory is; v_x = v cos θ

v_x = 12 cos 51

v_x = 7.55 m/s

D) The y-component of the shot's velocity at the beginning of its trajectory is; v_y = v sin θ

v_y = 12 sin 51

v_y = 9.32 m/s

Read more about Projectile Motion at; brainly.com/question/11049671

3 0
3 years ago
mary picks 15 flowers from her garden. if 3 out of 5 of the flowers are red, how many red flowers does mary pick?
Serhud [2]

Answer: Mary picks 9 red flowers.

Explanation:

3/5 = <em>x</em>/15

you first cross mulitiply 5 by <em>x </em>and 3 by 15

5<em>x</em>/5 = 45/5

then you divide 45 by 5 and get 9.

<em>x </em>= 9 red flowers  

6 0
3 years ago
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