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ratelena [41]
2 years ago
10

Which of the following are equivalent

Mathematics
1 answer:
Nataly_w [17]2 years ago
3 0
Where’s the question?
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In a triangle the length of two sides are 1.9m and 0.7m. What is the length of the third side, if you know that it should be a w
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It could be any number, is there choices?

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A few years ago, when the fuel tank in Sally’s car was completely empty, she paid $63 to fill the tank with 22.5 gallons of gaso
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2.8

Step-by-step explanation:

ur welcome i hope this helps

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A movie streaming website charges an initial fee of $80, plus $4 for each movie that is streamed. How many movies must be stream
pochemuha

Answer:

80 movies must be streamed.

Step-by-step explanation:

To find the average cost, you must divide the total cost by the number of movies watched.

When you watch 1 movie, you pay the initial fee of $80 plus a $4 purchase of the film.

The equation is shown as such:

average cost = (total cost)/(number of movies)

Your total cost can be represented as 4x + 80, while the number of movies is represented as x.

You want the average to equal 5, so your equation is shown as follows:

5 = (4x+80)/x

simplifying this, we get

5 = 4 + \frac{80}{x}

which can then be simplified to

1 = \frac{80}{x}

X = 80 movies.

4 0
3 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
Ron bought 6 tickets to a concert by the orchestra in his town. If he gave the cashier $75 and received $3 in change, how much d
Harman [31]
75-3= 72
72/6= 12
Each ticket costs $12.00
8 0
3 years ago
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