
where A is area
a is side a lets say its 8cm
b is side b lets say its 7 cm
theta is 28
The solution to the above factorization problem is given as f′(x)=4x³−3x²−10x−1. See steps below.
<h3>What are the steps to the above answer?</h3>
Step 1 - Take the derivative of both sides
f′(x)=d/dx(x^4−x^3−5x^2−x−6)
Step 2 - Use differentiation rule d/dx(f(x)±g(x))=d/dx(f(x))±d/dx(g(x))
f′(x)=d/dx(x4)−d/dx(x^3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−d/dx(x3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x2−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−1−dxd(6)
f′(x)=4x^3−3x^2−10x−1−0
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1 mm = 0.1 cm
(a) 5 mm
5 × 0.1 = 0.5
Fraction :- 5/0.5
5 ÷ 0.5 =10
Decimal:- 10
(b) 8 mm
8 × 0.1 = 0.8
Fraction:- 8/0.8
8 ÷ 0.8 = 10
Decimal:- 10