An ice skating competition features 8 skaters. How many different ways can the skaters finish the competition? how many differen

Question

2 years ago

6

t ways can 3 of the skaters finish first, second and third?.

1 answer:

yan [13] · Answer 1 · 2022-12-21T17:52:05+03:00

The number of ways the skaters can finish the competition is 40,320 ways

The different ways 3 of the skaters finish first, second and third is 56 ways

Given the following

If the skaters finish the competition, the number of different ways the skaters finish the competition is expressed as:

8! = 8*7*6*5*4*3*2

8! = 56*30*24

8! = 40,320.

The number of ways the skaters can finish the competition is 40,320 ways

If 3 of the skaters finish first, second and third, the number of ways this can be done is given as:

8C3 = 8!/(8-3)!3!

8C3 = 8!/5!3!

8C3 = 8*7*6*5!/5!3!

8C3 = 56 ways

Hence the different ways 3 of the skaters finish first, second and third is 56 ways

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