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3 years ago

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Need help with this problem

1 answer:

lions [1.4K]3 years ago

8 0

Since the shape is a square, it has 90° angles.

if cut in half, it creates a 45-45-90 triangle.
using this, you can use the ratio of 1:sqrt2 to find x. so the ratio would be x:6 to 1:sqrt2.

divide 6 by sqrt2 to find x, and then rationalize for it to become 6sqrt2/2, which would simplify even further to 3sqrt2

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Simplfy (x)^2(2xy^3)^5 plz help

Deffense [45]

Answer: 32x^7y^15

Step-by-step explanation:

(x)^2(2xy^3)^5

= x^2 * 32x^5y^15

= 32x^7y^15

5 0

3 years ago

Andrew wants to know how many 3/16 pound servings in a bag containing 7/8 pound of granola

Aleksandr-060686 [28]

Do 7/8 divided by 3/16.
Multiply by the reciprocal of 3/16 which is 16/3
7/8 x 16/3= 112/24
Simplify by dividing by 8 on top and bottom
14/3
Change it into a mixed number
Answer is 4 2/3

3 0

3 years ago

What is the Volume of the square pyramid? (Round to the nearest tenth as needed)

goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

$\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}$

b = base length = 25 mm

H = height

We have to find 'H' using Pythagorean theorem,

slant height (hypotenuse) = 28 mm

leg₁ = base length ÷ 2 = 25÷2 = 12.5

leg₂ = H

H² + (12.5)² = 28²

H² = 784 - 156.25

= 627.75

$\sf H = \sqrt{627.75}$

H = 25.01 mm

$\sf \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }$

= 5229 mm³

$\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}$

3 0

2 years ago

Read 2 more answers

Find the surface area of a sphere that has a volume of 288 pi cu. in.

icang [17]

Answer:

144

Step-by-step explanation:

The surface area of a sphere that has a volume of 288π cu in is 144 pi.

6 0

3 years ago

Read 2 more answers

Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min

alina1380 [7]

Answer:

$y=\frac{1}{2}x-2$

Step-by-step explanation:

We have been given two points on a line $(-6,-5)$ and $(-4,-4)$ . We are asked to write an equation passing through these points.

We will write our equation in slope-intercept form of equation $y=mx+b$ , where,

m = Slope of line,

b = Initial value or the y-intercept.

Let us find slope of given line using slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$

Let point $(-6,-5)=(x_1,y_1)$ and point $(-4,-4)=(x_2,y_2)$ .

$m=\frac{-4-(-5)}{-4-(-6)}$

$m=\frac{-4+5}{-4+6}$

$m=\frac{1}{2}$

Now, we will substitute $m=\frac{1}{2}$ and coordinates of point $(-6,-5)$ in slope-intercept form of equation as:

$-5=\frac{1}{2}*(-6)+b$

$-5=-3+b$

$-5+3=-3+3+b$

$-2=b$

Upon substituting $m=\frac{1}{2}$ and $b=-2$ in slope-intercept form of equation, we will get our required equation as:

$y=\frac{1}{2}x-2$

Therefore, our required equation would be $y=\frac{1}{2}x-2$ .

8 0

3 years ago