<h3>Answer</h3><h3 /><h3>

</h3>

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Answer:
Step-by-step explanation:
<h3>Given</h3>
<u>Inequality</u>: (x-1)(x+2)(2x-7)≤0
<h3>Solution: </h3>
<u>If we solve the corresponding equation (x-1)(x+2)(2x-7)²= 0, we get roots </u>
<u>We need to consider the following 4 intervals: </u>
- (−∞; −2), [−2; 1], (1; 3.5), (3.5; ∞)
<u>1st interval</u> (−∞; −2)
- The expression (x-1)(x+2)(2x-7)² is positive as two of the multiples are negative and one is always positive (square number), and therefore does not satisfy the inequality.
<u>2nd interval</u> [−2; 1]
- The expression is negative as only one of the multiples is negative, and therefore the interval (−1; 2) satisfies the inequality.
<u>3rd interval</u> (1; 3.5)
- The expression is positive as all the multiples are positive. Therefore, the interval (1; 3.5) also does not satisfy the inequality.
<u>4th interval</u>
- The expression is positive as above, and therefore also does not satisfy the inequality.
<u>So, the answer to the inequality is:
</u>
All you do is solve for z. So 8z-13=7. To solve for a variable you have to do the opposite to cancel out the numbers on each side. First you add 13 over to 7 to cancel out 13 on the z side. So 8z=20 is what you have left. Then you divide 8 on both sides to cancel out 8 on the z side. what you are left with is z=2.5. Lastly you plug and check. 8(2.5) - 13 = 7, 20-13=7. And thats correct so z is 2.5.
Answer:
5/6
Step-by-step explanation:
create a proportion:
(1/2÷3/5) = (x÷5/5)
cross-multiply to solve for 'x':
3/5x = 1/2
6x = 5
x = 5/6