The correct answer would be A- as it shows the correct median of 25.5
Answer:
P(X>17) = 0.979
Step-by-step explanation:
Probability that a camera is defective, p = 3% = 3/100 = 0.03
20 cameras were randomly selected.i.e sample size, n = 20
Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97
Probability that more than 17 cameras are working P ( X > 17)
This is a binomial distribution P(X = r) 

P(X>17) = P(X=18) + P(X=19) + P(X=20)
P(X=18) = 
P(X=18) = 
P(X=18) = 0.0988
P(X=19) = 
P(X=19) = 
P(X=19) = 0.3364
P(X=20) = 
P(X=20) = 
P(X=20) = 0.5438
P(X>17) = 0.0988 + 0.3364 + 0.5438
P(X>17) = 0.979
The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch
(6x -9) + 5= 2
= -54 + 5
= 2
Answer:
28m
7m/s
Step-by-step explanation:
sorry if it is wrong