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Westkost [7]
2 years ago
5

Write an equation of a parabola that has two x-intercepts and a minimum vertex.

Mathematics
2 answers:
Gre4nikov [31]2 years ago
6 0
The answer is B I hope this helps !!
LuckyWell [14K]2 years ago
5 0
B is correct ok yesssss
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HELP! BRAINLIEST!
kogti [31]

Answer:

Given that rotating 90 degrees clockwise around the origin switches the x andy values and makes the new y value negative, we can, for example, switch (2, 1) to (1, -2). 180 degrees clockwise simply makes both values negative (-2, -1), and 270 degrees clockwise switches them and makes the new y value negative  (-1, 2), we can plug those in to our JM endpoints to turn (-5, 1) into (-1, -5) and (-6, 2) into (-2, -6)

Step-by-step explanation:

6 0
2 years ago
44/35 as a mixed number
joja [24]

44/35 = 1 9/35

So, your answer is 1 9/35

4 0
3 years ago
Read 2 more answers
What is 9+9(2+4)÷3-2 equal
lesantik [10]
First, we must follow PEMDAS. (Parenthesis, exponents, division, multiplication, addition, and subtraction.).

We do what's in the parenthesis first.

9+9(2+4)÷3-2.

2+4=6.

Now our problem looks like this;

9+9(6)÷3-2 
OR
9+9×6÷3-2.

Anything in a parenthesis with no sign next to it, like this; 8(2), just means multiplication, so it would look like this: 8×2.

Next, we do all the multiplication in our problem.

9+9×6÷3-2.

9×6=54.

Now our problem looks like this;

9+54÷3-2.

Next, we do the division. 

9+54÷3-2

54÷3=18.

Now our problem looks like this;

9+18-2.

Next, we do the addition.

9+18-2

9+18=27

Now it looks like this;

27-2.

Finally, we subtract.

27-2=25.

Your final answer is 25!

Have a nice day! :)
7 0
2 years ago
4) A window is in the form of a rectangle surmounted by a semicircle. The rectangle is of clear glass, whereas the semicircle is
lisov135 [29]

Answer:

l=0.1401P\\

w =0.2801P

where P = perimeter

Step-by-step explanation:

Given that a window is in the form of a rectangle surmounted by a semicircle.

Perimeter of window =2l+\pid/2+w

P= 2l+3.14 (w/2)+w

Or P = 2l+2.57w\\l = \frac{P-2.57w}{2}

To allow maximum light we must have maximum area

Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle

A=lw +\pi \frac{w^2}{8}

A=lw +\pi \frac{w^2}{8}\\A=w*\frac{P-2.57w}{2}+0.3925w^2\\2A= Pw-2.57w^2+(0.785w^2)\\2A' = P-5.14w+1.57 w\\2A" =-5.14+1.57

Hence we get maximum area when i derivative is 0

i.e. P-5.14w+1.57 w=0\\3.57w =P\\w = \frac{P}{3.57} =0.2801P

l = \frac{P-2.57w}{2}\\l = 0.1401P

Dimensions can be

l=0.1401P\\w =0.2801P

5 0
3 years ago
Brian has basketball cards and 5 baseball cards what fraction of brians card are baseball cards
stich3 [128]
How many basketball cards
8 0
3 years ago
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