The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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If two triangles are similar, then their side lengths are proportional.
RS / JK = RT / JL
5 / x = 4 / 7
4x = 35
x = 35/4 = 8.75
RT / JL = TS / LK
4 / 7 = 6 / (y + 2)
42 = 4(y + 2)
42 = 4y + 4
4y = 38
y = 38/4 = 9.5
LK = 9.5 + 2 = 11.5 cm
JK = x = 8.75
Hope this helps!
Answer:
b
Step-by-step explanation:
No because each time it goes up by (1) and in the last one it goes up (2 times) and then decreases (4 times) on the right.
Answer:
468 ways
Step-by-step explanation:
Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts
To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.
Solution:
A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.
Number of appetizers = 5
Number of main courses = 4
Number of desserts = 8
Number of ways of choosing k terms from n terms = 
Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts = 
So, this can be done in 468 ways.
