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kumpel [21]
3 years ago
12

Please help me i’m so lost Determine the lengths of AB and AC in the right triangle. You may give your answers in radical

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

Using the sine/ cosine ratios in the right triangle and the exact values

sin30° = \frac{1}{2} , cos30° = \frac{\sqrt{3} }{2} , then

sin30° = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{6}{AB} = \frac{1}{2} ( cross- multiply )

AB = 12

cos30° = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{AC}{12} = \frac{\sqrt{3} }{2} ( cross- multiply )

2 AC = 12\sqrt{3} ( divide both sides by 2 )

AC = 6\sqrt{3}

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